how to embed the php image path in javascript
var arrow2 ="<?php echo base_url() ?>/assets/images/apply_coupon/arrow-2.png" ;
var arrow1 ="<?php echo base_url() ?>/assets/images/apply_coupon/arrow-1.png" ;
img_array= new Array($arrow2,$arrow1);
I have created one img_array, and I have passed the php variable into it is it the correct format or not?
javascript php arrays
edited Nov 23 '18 at 6:54
Nick
29k121941
asked Nov 23 '18 at 6:48
Kavya SenthilKavya Senthil
12
add a comment |
var arrow2 ="<?php echo base_url() ?>/assets/images/apply_coupon/arrow-2.png" ;
var arrow1 ="<?php echo base_url() ?>/assets/images/apply_coupon/arrow-1.png" ;
img_array= new Array($arrow2,$arrow1);
I have created one img_array, and I have passed the php variable into it is it the correct format or not?
javascript php arrays
edited Nov 23 '18 at 6:54
Nick
29k121941
asked Nov 23 '18 at 6:48
Kavya SenthilKavya Senthil
12
1
var arrow2 and arrow1 both are JS variable. Why did u make it as php variable? Change it to => img_array= new Array( arrow2, arrow1);
– Aravind Bhat K
Nov 23 '18 at 6:53
add a comment |
var arrow2 ="<?php echo base_url() ?>/assets/images/apply_coupon/arrow-2.png" ;
var arrow1 ="<?php echo base_url() ?>/assets/images/apply_coupon/arrow-1.png" ;
img_array= new Array($arrow2,$arrow1);
I have created one img_array, and I have passed the php variable into it is it the correct format or not?
javascript php arrays
edited Nov 23 '18 at 6:54
Nick
29k121941
asked Nov 23 '18 at 6:48
Kavya SenthilKavya Senthil
12
var arrow2 ="<?php echo base_url() ?>/assets/images/apply_coupon/arrow-2.png" ;
var arrow1 ="<?php echo base_url() ?>/assets/images/apply_coupon/arrow-1.png" ;
img_array= new Array($arrow2,$arrow1);
I have created one img_array, and I have passed the php variable into it is it the correct format or not?
javascript php arrays
javascript php arrays
edited Nov 23 '18 at 6:54
Nick
29k121941
asked Nov 23 '18 at 6:48
Kavya SenthilKavya Senthil
12
edited Nov 23 '18 at 6:54
Nick
29k121941
asked Nov 23 '18 at 6:48
Kavya SenthilKavya Senthil
12
edited Nov 23 '18 at 6:54
Nick
29k121941
edited Nov 23 '18 at 6:54
Nick
29k121941
edited Nov 23 '18 at 6:54
Nick
29k121941
29k121941
asked Nov 23 '18 at 6:48
Kavya SenthilKavya Senthil
12
asked Nov 23 '18 at 6:48
Kavya SenthilKavya Senthil
12
asked Nov 23 '18 at 6:48
Kavya SenthilKavya Senthil
12
12
1
var arrow2 and arrow1 both are JS variable. Why did u make it as php variable? Change it to => img_array= new Array( arrow2, arrow1);
– Aravind Bhat K
Nov 23 '18 at 6:53
add a comment |
1
var arrow2 and arrow1 both are JS variable. Why did u make it as php variable? Change it to => img_array= new Array( arrow2, arrow1);
– Aravind Bhat K
Nov 23 '18 at 6:53
1
1
var arrow2 and arrow1 both are JS variable. Why did u make it as php variable? Change it to => img_array= new Array( arrow2, arrow1);
– Aravind Bhat K
Nov 23 '18 at 6:53
var arrow2 and arrow1 both are JS variable. Why did u make it as php variable? Change it to => img_array= new Array( arrow2, arrow1);
– Aravind Bhat K
Nov 23 '18 at 6:53
add a comment |
1 Answer
1
active
oldest
votes
change variable names used for making new array
`var img_array= new Array(arrow2, arrow1);
or
var img_array= [arrow2, arrow1];
`
or replace the var arrow1 to $arrow1 if you want to use dollar($) sign
answered Nov 23 '18 at 7:09
AkhileshAkhilesh
626
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53441848%2fhow-to-embed-the-php-image-path-in-javascript%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
change variable names used for making new array
`var img_array= new Array(arrow2, arrow1);
or
var img_array= [arrow2, arrow1];
`
or replace the var arrow1 to $arrow1 if you want to use dollar($) sign
answered Nov 23 '18 at 7:09
AkhileshAkhilesh
626
add a comment |
change variable names used for making new array
`var img_array= new Array(arrow2, arrow1);
or
var img_array= [arrow2, arrow1];
`
or replace the var arrow1 to $arrow1 if you want to use dollar($) sign
answered Nov 23 '18 at 7:09
AkhileshAkhilesh
626
add a comment |
change variable names used for making new array
`var img_array= new Array(arrow2, arrow1);
or
var img_array= [arrow2, arrow1];
`
or replace the var arrow1 to $arrow1 if you want to use dollar($) sign
answered Nov 23 '18 at 7:09
AkhileshAkhilesh
626
change variable names used for making new array
`var img_array= new Array(arrow2, arrow1);
or
var img_array= [arrow2, arrow1];
`
or replace the var arrow1 to $arrow1 if you want to use dollar($) sign
answered Nov 23 '18 at 7:09
AkhileshAkhilesh
626
answered Nov 23 '18 at 7:09
AkhileshAkhilesh
626
answered Nov 23 '18 at 7:09
AkhileshAkhilesh
626
answered Nov 23 '18 at 7:09
AkhileshAkhilesh
626
626
add a comment |
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53441848%2fhow-to-embed-the-php-image-path-in-javascript%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
1
var arrow2 and arrow1 both are JS variable. Why did u make it as php variable? Change it to => img_array= new Array( arrow2, arrow1);
– Aravind Bhat K
Nov 23 '18 at 6:53