check balanced parenthesis in python











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I want to make a code that can match parenthesis.
Assumptions are that parenthesis is given by string, and the input is given by list.



So below is my code:
I got the error that:




'AttributeError: 'list' object has no attribute 'parenthesis''




Please let me know what's wrong with my code.



def push(item):  
stack.append(item)


def peek():
if len(stack) != 0:
return stack[-1]

def pop(): #delete step
if len(stack) != 0:
item = stack.pop(-1)
return item

def check(item):
global stack1
stack1 =
global stack2
stack2 =
if item == '{':
stack1.push('1')
elif item == '}':
stack1.pop()
elif item == '(':
stack2.push('2')
elif item == ')':
stack2.pop()

def parenthesis(self):
for i in len(self):
tail = self.peek
tail.check
self.pop()
if len(stack1) == 0 & len(stack2) ==0 :
print('pass')
else:
print('fail')

stack =
push('{')
push('}')
stack.parenthesis()









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  • Try to implement stack in line with OOP paradigm and avoid using global variables. For example you may create a Stack class
    – artona
    Nov 19 at 11:47










  • thank you artona!! and i'll try Stack class. Can i ask one question that why do you recommend to avoid using global variables? they have some disadvantages?
    – Heewon
    Nov 19 at 11:50












  • Making long story short: they are dangerous because you can forget about them when developing your program. Here is the better thread on this: stackoverflow.com/questions/423379/…
    – artona
    Nov 19 at 11:53










  • artona thank you . have a nice day :)
    – Heewon
    Nov 19 at 11:55










  • it looks like your code was copied from a source that originally had a stack class, i suggest you look into the original code
    – AntiMatterDynamite
    Nov 19 at 11:57















up vote
0
down vote

favorite












I want to make a code that can match parenthesis.
Assumptions are that parenthesis is given by string, and the input is given by list.



So below is my code:
I got the error that:




'AttributeError: 'list' object has no attribute 'parenthesis''




Please let me know what's wrong with my code.



def push(item):  
stack.append(item)


def peek():
if len(stack) != 0:
return stack[-1]

def pop(): #delete step
if len(stack) != 0:
item = stack.pop(-1)
return item

def check(item):
global stack1
stack1 =
global stack2
stack2 =
if item == '{':
stack1.push('1')
elif item == '}':
stack1.pop()
elif item == '(':
stack2.push('2')
elif item == ')':
stack2.pop()

def parenthesis(self):
for i in len(self):
tail = self.peek
tail.check
self.pop()
if len(stack1) == 0 & len(stack2) ==0 :
print('pass')
else:
print('fail')

stack =
push('{')
push('}')
stack.parenthesis()









share|improve this question









New contributor




Heewon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.




















  • Try to implement stack in line with OOP paradigm and avoid using global variables. For example you may create a Stack class
    – artona
    Nov 19 at 11:47










  • thank you artona!! and i'll try Stack class. Can i ask one question that why do you recommend to avoid using global variables? they have some disadvantages?
    – Heewon
    Nov 19 at 11:50












  • Making long story short: they are dangerous because you can forget about them when developing your program. Here is the better thread on this: stackoverflow.com/questions/423379/…
    – artona
    Nov 19 at 11:53










  • artona thank you . have a nice day :)
    – Heewon
    Nov 19 at 11:55










  • it looks like your code was copied from a source that originally had a stack class, i suggest you look into the original code
    – AntiMatterDynamite
    Nov 19 at 11:57













up vote
0
down vote

favorite









up vote
0
down vote

favorite











I want to make a code that can match parenthesis.
Assumptions are that parenthesis is given by string, and the input is given by list.



So below is my code:
I got the error that:




'AttributeError: 'list' object has no attribute 'parenthesis''




Please let me know what's wrong with my code.



def push(item):  
stack.append(item)


def peek():
if len(stack) != 0:
return stack[-1]

def pop(): #delete step
if len(stack) != 0:
item = stack.pop(-1)
return item

def check(item):
global stack1
stack1 =
global stack2
stack2 =
if item == '{':
stack1.push('1')
elif item == '}':
stack1.pop()
elif item == '(':
stack2.push('2')
elif item == ')':
stack2.pop()

def parenthesis(self):
for i in len(self):
tail = self.peek
tail.check
self.pop()
if len(stack1) == 0 & len(stack2) ==0 :
print('pass')
else:
print('fail')

stack =
push('{')
push('}')
stack.parenthesis()









share|improve this question









New contributor




Heewon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











I want to make a code that can match parenthesis.
Assumptions are that parenthesis is given by string, and the input is given by list.



So below is my code:
I got the error that:




'AttributeError: 'list' object has no attribute 'parenthesis''




Please let me know what's wrong with my code.



def push(item):  
stack.append(item)


def peek():
if len(stack) != 0:
return stack[-1]

def pop(): #delete step
if len(stack) != 0:
item = stack.pop(-1)
return item

def check(item):
global stack1
stack1 =
global stack2
stack2 =
if item == '{':
stack1.push('1')
elif item == '}':
stack1.pop()
elif item == '(':
stack2.push('2')
elif item == ')':
stack2.pop()

def parenthesis(self):
for i in len(self):
tail = self.peek
tail.check
self.pop()
if len(stack1) == 0 & len(stack2) ==0 :
print('pass')
else:
print('fail')

stack =
push('{')
push('}')
stack.parenthesis()






python xcode list stack parentheses






share|improve this question









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Heewon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question









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Heewon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|improve this question




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edited Nov 19 at 13:23







user10638812













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asked Nov 19 at 11:43









Heewon

1




1




New contributor




Heewon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





Heewon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






Heewon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.












  • Try to implement stack in line with OOP paradigm and avoid using global variables. For example you may create a Stack class
    – artona
    Nov 19 at 11:47










  • thank you artona!! and i'll try Stack class. Can i ask one question that why do you recommend to avoid using global variables? they have some disadvantages?
    – Heewon
    Nov 19 at 11:50












  • Making long story short: they are dangerous because you can forget about them when developing your program. Here is the better thread on this: stackoverflow.com/questions/423379/…
    – artona
    Nov 19 at 11:53










  • artona thank you . have a nice day :)
    – Heewon
    Nov 19 at 11:55










  • it looks like your code was copied from a source that originally had a stack class, i suggest you look into the original code
    – AntiMatterDynamite
    Nov 19 at 11:57


















  • Try to implement stack in line with OOP paradigm and avoid using global variables. For example you may create a Stack class
    – artona
    Nov 19 at 11:47










  • thank you artona!! and i'll try Stack class. Can i ask one question that why do you recommend to avoid using global variables? they have some disadvantages?
    – Heewon
    Nov 19 at 11:50












  • Making long story short: they are dangerous because you can forget about them when developing your program. Here is the better thread on this: stackoverflow.com/questions/423379/…
    – artona
    Nov 19 at 11:53










  • artona thank you . have a nice day :)
    – Heewon
    Nov 19 at 11:55










  • it looks like your code was copied from a source that originally had a stack class, i suggest you look into the original code
    – AntiMatterDynamite
    Nov 19 at 11:57
















Try to implement stack in line with OOP paradigm and avoid using global variables. For example you may create a Stack class
– artona
Nov 19 at 11:47




Try to implement stack in line with OOP paradigm and avoid using global variables. For example you may create a Stack class
– artona
Nov 19 at 11:47












thank you artona!! and i'll try Stack class. Can i ask one question that why do you recommend to avoid using global variables? they have some disadvantages?
– Heewon
Nov 19 at 11:50






thank you artona!! and i'll try Stack class. Can i ask one question that why do you recommend to avoid using global variables? they have some disadvantages?
– Heewon
Nov 19 at 11:50














Making long story short: they are dangerous because you can forget about them when developing your program. Here is the better thread on this: stackoverflow.com/questions/423379/…
– artona
Nov 19 at 11:53




Making long story short: they are dangerous because you can forget about them when developing your program. Here is the better thread on this: stackoverflow.com/questions/423379/…
– artona
Nov 19 at 11:53












artona thank you . have a nice day :)
– Heewon
Nov 19 at 11:55




artona thank you . have a nice day :)
– Heewon
Nov 19 at 11:55












it looks like your code was copied from a source that originally had a stack class, i suggest you look into the original code
– AntiMatterDynamite
Nov 19 at 11:57




it looks like your code was copied from a source that originally had a stack class, i suggest you look into the original code
– AntiMatterDynamite
Nov 19 at 11:57

















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