Conditional Formatting Cell R DataTable











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I need to implement conditional formatting in my datatable. See an example below. What I need is to highlight the third row, "PercentDone", based on if that number is greater than the thresholds in rows 4 and 5.



If the number is greater than 50%, I would like to highlight it green.



If it is between 25% and 50%, I would like to highlight it yellow.



If it is under 25%, I would like to highlight it red.



This is similar to something someone would do in Excel with conditional formatting, I am just unsure as to how to implement it in a datatable in R.



In the example below, the 46% in column 1 should be yellow, the 11% in column 2 should be red, and the 65% in column 3 should be green.



df = data.frame(
c(51, 59, '46%', '25%', '50%'),
c(12, 93, '11%', '25%', '50%'),
c(40, 22, '65%', '25%', '50%'))

colnames(df) = c('Location1', 'Location2', 'Location3')
rownames(df) = c('Done', 'Need', 'PercentDone', 'Threshold1', 'Threshold2')

DT = datatable(df) %>%
formatStyle(...)









share|improve this question






















  • Do the thresholds change each time or are they fixed?
    – GGamba
    Jun 6 '17 at 1:07












  • Is the mixed-format (numeric and character) for each column of your df done on purpose?
    – Adam Quek
    Jun 6 '17 at 3:38










  • Thank you for your responses. Yes, it's on purpose, as the table must look this way. I suppose getting the number version of row 3 could be done by as.numeric(gsub('%', '', df[3,])). The thresholds are fixed, which does make it a little easier. I'm mainly confused by what to put in the formatStyle().
    – tsouchlarakis
    Jun 6 '17 at 16:14












  • Does anyone know of a way to achieve this?
    – tsouchlarakis
    Jul 13 '17 at 20:54















up vote
0
down vote

favorite












I need to implement conditional formatting in my datatable. See an example below. What I need is to highlight the third row, "PercentDone", based on if that number is greater than the thresholds in rows 4 and 5.



If the number is greater than 50%, I would like to highlight it green.



If it is between 25% and 50%, I would like to highlight it yellow.



If it is under 25%, I would like to highlight it red.



This is similar to something someone would do in Excel with conditional formatting, I am just unsure as to how to implement it in a datatable in R.



In the example below, the 46% in column 1 should be yellow, the 11% in column 2 should be red, and the 65% in column 3 should be green.



df = data.frame(
c(51, 59, '46%', '25%', '50%'),
c(12, 93, '11%', '25%', '50%'),
c(40, 22, '65%', '25%', '50%'))

colnames(df) = c('Location1', 'Location2', 'Location3')
rownames(df) = c('Done', 'Need', 'PercentDone', 'Threshold1', 'Threshold2')

DT = datatable(df) %>%
formatStyle(...)









share|improve this question






















  • Do the thresholds change each time or are they fixed?
    – GGamba
    Jun 6 '17 at 1:07












  • Is the mixed-format (numeric and character) for each column of your df done on purpose?
    – Adam Quek
    Jun 6 '17 at 3:38










  • Thank you for your responses. Yes, it's on purpose, as the table must look this way. I suppose getting the number version of row 3 could be done by as.numeric(gsub('%', '', df[3,])). The thresholds are fixed, which does make it a little easier. I'm mainly confused by what to put in the formatStyle().
    – tsouchlarakis
    Jun 6 '17 at 16:14












  • Does anyone know of a way to achieve this?
    – tsouchlarakis
    Jul 13 '17 at 20:54













up vote
0
down vote

favorite









up vote
0
down vote

favorite











I need to implement conditional formatting in my datatable. See an example below. What I need is to highlight the third row, "PercentDone", based on if that number is greater than the thresholds in rows 4 and 5.



If the number is greater than 50%, I would like to highlight it green.



If it is between 25% and 50%, I would like to highlight it yellow.



If it is under 25%, I would like to highlight it red.



This is similar to something someone would do in Excel with conditional formatting, I am just unsure as to how to implement it in a datatable in R.



In the example below, the 46% in column 1 should be yellow, the 11% in column 2 should be red, and the 65% in column 3 should be green.



df = data.frame(
c(51, 59, '46%', '25%', '50%'),
c(12, 93, '11%', '25%', '50%'),
c(40, 22, '65%', '25%', '50%'))

colnames(df) = c('Location1', 'Location2', 'Location3')
rownames(df) = c('Done', 'Need', 'PercentDone', 'Threshold1', 'Threshold2')

DT = datatable(df) %>%
formatStyle(...)









share|improve this question













I need to implement conditional formatting in my datatable. See an example below. What I need is to highlight the third row, "PercentDone", based on if that number is greater than the thresholds in rows 4 and 5.



If the number is greater than 50%, I would like to highlight it green.



If it is between 25% and 50%, I would like to highlight it yellow.



If it is under 25%, I would like to highlight it red.



This is similar to something someone would do in Excel with conditional formatting, I am just unsure as to how to implement it in a datatable in R.



In the example below, the 46% in column 1 should be yellow, the 11% in column 2 should be red, and the 65% in column 3 should be green.



df = data.frame(
c(51, 59, '46%', '25%', '50%'),
c(12, 93, '11%', '25%', '50%'),
c(40, 22, '65%', '25%', '50%'))

colnames(df) = c('Location1', 'Location2', 'Location3')
rownames(df) = c('Done', 'Need', 'PercentDone', 'Threshold1', 'Threshold2')

DT = datatable(df) %>%
formatStyle(...)






r datatable






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Jun 5 '17 at 21:35









tsouchlarakis

354518




354518












  • Do the thresholds change each time or are they fixed?
    – GGamba
    Jun 6 '17 at 1:07












  • Is the mixed-format (numeric and character) for each column of your df done on purpose?
    – Adam Quek
    Jun 6 '17 at 3:38










  • Thank you for your responses. Yes, it's on purpose, as the table must look this way. I suppose getting the number version of row 3 could be done by as.numeric(gsub('%', '', df[3,])). The thresholds are fixed, which does make it a little easier. I'm mainly confused by what to put in the formatStyle().
    – tsouchlarakis
    Jun 6 '17 at 16:14












  • Does anyone know of a way to achieve this?
    – tsouchlarakis
    Jul 13 '17 at 20:54


















  • Do the thresholds change each time or are they fixed?
    – GGamba
    Jun 6 '17 at 1:07












  • Is the mixed-format (numeric and character) for each column of your df done on purpose?
    – Adam Quek
    Jun 6 '17 at 3:38










  • Thank you for your responses. Yes, it's on purpose, as the table must look this way. I suppose getting the number version of row 3 could be done by as.numeric(gsub('%', '', df[3,])). The thresholds are fixed, which does make it a little easier. I'm mainly confused by what to put in the formatStyle().
    – tsouchlarakis
    Jun 6 '17 at 16:14












  • Does anyone know of a way to achieve this?
    – tsouchlarakis
    Jul 13 '17 at 20:54
















Do the thresholds change each time or are they fixed?
– GGamba
Jun 6 '17 at 1:07






Do the thresholds change each time or are they fixed?
– GGamba
Jun 6 '17 at 1:07














Is the mixed-format (numeric and character) for each column of your df done on purpose?
– Adam Quek
Jun 6 '17 at 3:38




Is the mixed-format (numeric and character) for each column of your df done on purpose?
– Adam Quek
Jun 6 '17 at 3:38












Thank you for your responses. Yes, it's on purpose, as the table must look this way. I suppose getting the number version of row 3 could be done by as.numeric(gsub('%', '', df[3,])). The thresholds are fixed, which does make it a little easier. I'm mainly confused by what to put in the formatStyle().
– tsouchlarakis
Jun 6 '17 at 16:14






Thank you for your responses. Yes, it's on purpose, as the table must look this way. I suppose getting the number version of row 3 could be done by as.numeric(gsub('%', '', df[3,])). The thresholds are fixed, which does make it a little easier. I'm mainly confused by what to put in the formatStyle().
– tsouchlarakis
Jun 6 '17 at 16:14














Does anyone know of a way to achieve this?
– tsouchlarakis
Jul 13 '17 at 20:54




Does anyone know of a way to achieve this?
– tsouchlarakis
Jul 13 '17 at 20:54












1 Answer
1






active

oldest

votes

















up vote
1
down vote



accepted










Late reply, but might prove useful for someone else so I'm posting.

If transposing the table is not a problem, you can try the following.


The final table should look like this:



enter image description here



DF = data.frame(
c(51, 59, '46%', '25%', '50%'),
c(12, 93, '11%', '25%', '50%'),
c(40, 22, '65%', '25%', '50%'), stringsAsFactors = FALSE )# variables as chr, w/o factor levels)


colnames(DF) = c('Location1', 'Location2', 'Location3')
rownames(DF) = c('Done', 'Need', 'PercentDone', 'Threshold1', 'Threshold2')

head(DF)


Retrieve only the numbers from the percentages, convert to numeric to be able to perform the comparisons:



# Define function for retrieving digits; One-liner courtesy of @stla at GitHub
Numextract <- function(string){ unlist(regmatches(string,gregexpr("[[:digit:]]+\.*[[:digit:]]*",string)))}

# Apply Numextract to all dataframe;
# retrieves only digits but still class is chr
DF [,] <- lapply(DF[,], Numextract)

# Convert to numeric to allow for comparison
DF [,] <- lapply(DF[,], as.numeric)

# Transpose dataframe to access the `PercentDone` as a column
DF = t(DF)


Consider removing the values from the dataframe and have as vars



Threshold1 = 25
Threshold2 = 50


Customizing datatable: Highlight PercentDone



DT::datatable(DF, 
filter = "bottom",
caption = "I am the title",


# OPTIONS:
options = list(

initComplete = JS(
"function(settings, json) {",
"$(this.api().table().header()).css({'background-color': '#000', 'color': '#fff'});",
"}"),
columnDefs = list(list(targets = length(colnames(DF)), visible = TRUE)))) %>%

# Change fontsize of cell values
formatStyle(columns = c(1:length(colnames(df))),
fontSize = "85%",
fontFamily = "Verdana")%>%



# Format column based on P.Value levels
formatStyle(fontWeight = 'bold',
# Format this:
"PercentDone",

# Font color
color = styleInterval(c(0.0), c('black', 'black')),
backgroundColor = styleInterval(c(Threshold1, Threshold2),
c('lightgreen', '#f4d35e', "tomato"))) -> fancyTable


# Print customized color-coded datatable:
fancyTable





share|improve this answer























  • I'd suggest uploading the image using StackOverflow's built-in system, especially if you are linking to someone else's dropbox. In the event the link goes dead.
    – Anonymous coward
    Nov 14 at 15:24






  • 1




    Thanks for your answer. I have moved on from this project in time, but I hope this may help someone in the future. Thanks again.
    – tsouchlarakis
    Nov 14 at 19:04










  • @Anonymouscoward Thanks for suggestion. I am new and posting a picture is not allowed unless one reaches a certain number of reputation points. Ideas on how to alt post an image very welcome
    – cgpu
    Nov 15 at 14:18











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
1
down vote



accepted










Late reply, but might prove useful for someone else so I'm posting.

If transposing the table is not a problem, you can try the following.


The final table should look like this:



enter image description here



DF = data.frame(
c(51, 59, '46%', '25%', '50%'),
c(12, 93, '11%', '25%', '50%'),
c(40, 22, '65%', '25%', '50%'), stringsAsFactors = FALSE )# variables as chr, w/o factor levels)


colnames(DF) = c('Location1', 'Location2', 'Location3')
rownames(DF) = c('Done', 'Need', 'PercentDone', 'Threshold1', 'Threshold2')

head(DF)


Retrieve only the numbers from the percentages, convert to numeric to be able to perform the comparisons:



# Define function for retrieving digits; One-liner courtesy of @stla at GitHub
Numextract <- function(string){ unlist(regmatches(string,gregexpr("[[:digit:]]+\.*[[:digit:]]*",string)))}

# Apply Numextract to all dataframe;
# retrieves only digits but still class is chr
DF [,] <- lapply(DF[,], Numextract)

# Convert to numeric to allow for comparison
DF [,] <- lapply(DF[,], as.numeric)

# Transpose dataframe to access the `PercentDone` as a column
DF = t(DF)


Consider removing the values from the dataframe and have as vars



Threshold1 = 25
Threshold2 = 50


Customizing datatable: Highlight PercentDone



DT::datatable(DF, 
filter = "bottom",
caption = "I am the title",


# OPTIONS:
options = list(

initComplete = JS(
"function(settings, json) {",
"$(this.api().table().header()).css({'background-color': '#000', 'color': '#fff'});",
"}"),
columnDefs = list(list(targets = length(colnames(DF)), visible = TRUE)))) %>%

# Change fontsize of cell values
formatStyle(columns = c(1:length(colnames(df))),
fontSize = "85%",
fontFamily = "Verdana")%>%



# Format column based on P.Value levels
formatStyle(fontWeight = 'bold',
# Format this:
"PercentDone",

# Font color
color = styleInterval(c(0.0), c('black', 'black')),
backgroundColor = styleInterval(c(Threshold1, Threshold2),
c('lightgreen', '#f4d35e', "tomato"))) -> fancyTable


# Print customized color-coded datatable:
fancyTable





share|improve this answer























  • I'd suggest uploading the image using StackOverflow's built-in system, especially if you are linking to someone else's dropbox. In the event the link goes dead.
    – Anonymous coward
    Nov 14 at 15:24






  • 1




    Thanks for your answer. I have moved on from this project in time, but I hope this may help someone in the future. Thanks again.
    – tsouchlarakis
    Nov 14 at 19:04










  • @Anonymouscoward Thanks for suggestion. I am new and posting a picture is not allowed unless one reaches a certain number of reputation points. Ideas on how to alt post an image very welcome
    – cgpu
    Nov 15 at 14:18















up vote
1
down vote



accepted










Late reply, but might prove useful for someone else so I'm posting.

If transposing the table is not a problem, you can try the following.


The final table should look like this:



enter image description here



DF = data.frame(
c(51, 59, '46%', '25%', '50%'),
c(12, 93, '11%', '25%', '50%'),
c(40, 22, '65%', '25%', '50%'), stringsAsFactors = FALSE )# variables as chr, w/o factor levels)


colnames(DF) = c('Location1', 'Location2', 'Location3')
rownames(DF) = c('Done', 'Need', 'PercentDone', 'Threshold1', 'Threshold2')

head(DF)


Retrieve only the numbers from the percentages, convert to numeric to be able to perform the comparisons:



# Define function for retrieving digits; One-liner courtesy of @stla at GitHub
Numextract <- function(string){ unlist(regmatches(string,gregexpr("[[:digit:]]+\.*[[:digit:]]*",string)))}

# Apply Numextract to all dataframe;
# retrieves only digits but still class is chr
DF [,] <- lapply(DF[,], Numextract)

# Convert to numeric to allow for comparison
DF [,] <- lapply(DF[,], as.numeric)

# Transpose dataframe to access the `PercentDone` as a column
DF = t(DF)


Consider removing the values from the dataframe and have as vars



Threshold1 = 25
Threshold2 = 50


Customizing datatable: Highlight PercentDone



DT::datatable(DF, 
filter = "bottom",
caption = "I am the title",


# OPTIONS:
options = list(

initComplete = JS(
"function(settings, json) {",
"$(this.api().table().header()).css({'background-color': '#000', 'color': '#fff'});",
"}"),
columnDefs = list(list(targets = length(colnames(DF)), visible = TRUE)))) %>%

# Change fontsize of cell values
formatStyle(columns = c(1:length(colnames(df))),
fontSize = "85%",
fontFamily = "Verdana")%>%



# Format column based on P.Value levels
formatStyle(fontWeight = 'bold',
# Format this:
"PercentDone",

# Font color
color = styleInterval(c(0.0), c('black', 'black')),
backgroundColor = styleInterval(c(Threshold1, Threshold2),
c('lightgreen', '#f4d35e', "tomato"))) -> fancyTable


# Print customized color-coded datatable:
fancyTable





share|improve this answer























  • I'd suggest uploading the image using StackOverflow's built-in system, especially if you are linking to someone else's dropbox. In the event the link goes dead.
    – Anonymous coward
    Nov 14 at 15:24






  • 1




    Thanks for your answer. I have moved on from this project in time, but I hope this may help someone in the future. Thanks again.
    – tsouchlarakis
    Nov 14 at 19:04










  • @Anonymouscoward Thanks for suggestion. I am new and posting a picture is not allowed unless one reaches a certain number of reputation points. Ideas on how to alt post an image very welcome
    – cgpu
    Nov 15 at 14:18













up vote
1
down vote



accepted







up vote
1
down vote



accepted






Late reply, but might prove useful for someone else so I'm posting.

If transposing the table is not a problem, you can try the following.


The final table should look like this:



enter image description here



DF = data.frame(
c(51, 59, '46%', '25%', '50%'),
c(12, 93, '11%', '25%', '50%'),
c(40, 22, '65%', '25%', '50%'), stringsAsFactors = FALSE )# variables as chr, w/o factor levels)


colnames(DF) = c('Location1', 'Location2', 'Location3')
rownames(DF) = c('Done', 'Need', 'PercentDone', 'Threshold1', 'Threshold2')

head(DF)


Retrieve only the numbers from the percentages, convert to numeric to be able to perform the comparisons:



# Define function for retrieving digits; One-liner courtesy of @stla at GitHub
Numextract <- function(string){ unlist(regmatches(string,gregexpr("[[:digit:]]+\.*[[:digit:]]*",string)))}

# Apply Numextract to all dataframe;
# retrieves only digits but still class is chr
DF [,] <- lapply(DF[,], Numextract)

# Convert to numeric to allow for comparison
DF [,] <- lapply(DF[,], as.numeric)

# Transpose dataframe to access the `PercentDone` as a column
DF = t(DF)


Consider removing the values from the dataframe and have as vars



Threshold1 = 25
Threshold2 = 50


Customizing datatable: Highlight PercentDone



DT::datatable(DF, 
filter = "bottom",
caption = "I am the title",


# OPTIONS:
options = list(

initComplete = JS(
"function(settings, json) {",
"$(this.api().table().header()).css({'background-color': '#000', 'color': '#fff'});",
"}"),
columnDefs = list(list(targets = length(colnames(DF)), visible = TRUE)))) %>%

# Change fontsize of cell values
formatStyle(columns = c(1:length(colnames(df))),
fontSize = "85%",
fontFamily = "Verdana")%>%



# Format column based on P.Value levels
formatStyle(fontWeight = 'bold',
# Format this:
"PercentDone",

# Font color
color = styleInterval(c(0.0), c('black', 'black')),
backgroundColor = styleInterval(c(Threshold1, Threshold2),
c('lightgreen', '#f4d35e', "tomato"))) -> fancyTable


# Print customized color-coded datatable:
fancyTable





share|improve this answer














Late reply, but might prove useful for someone else so I'm posting.

If transposing the table is not a problem, you can try the following.


The final table should look like this:



enter image description here



DF = data.frame(
c(51, 59, '46%', '25%', '50%'),
c(12, 93, '11%', '25%', '50%'),
c(40, 22, '65%', '25%', '50%'), stringsAsFactors = FALSE )# variables as chr, w/o factor levels)


colnames(DF) = c('Location1', 'Location2', 'Location3')
rownames(DF) = c('Done', 'Need', 'PercentDone', 'Threshold1', 'Threshold2')

head(DF)


Retrieve only the numbers from the percentages, convert to numeric to be able to perform the comparisons:



# Define function for retrieving digits; One-liner courtesy of @stla at GitHub
Numextract <- function(string){ unlist(regmatches(string,gregexpr("[[:digit:]]+\.*[[:digit:]]*",string)))}

# Apply Numextract to all dataframe;
# retrieves only digits but still class is chr
DF [,] <- lapply(DF[,], Numextract)

# Convert to numeric to allow for comparison
DF [,] <- lapply(DF[,], as.numeric)

# Transpose dataframe to access the `PercentDone` as a column
DF = t(DF)


Consider removing the values from the dataframe and have as vars



Threshold1 = 25
Threshold2 = 50


Customizing datatable: Highlight PercentDone



DT::datatable(DF, 
filter = "bottom",
caption = "I am the title",


# OPTIONS:
options = list(

initComplete = JS(
"function(settings, json) {",
"$(this.api().table().header()).css({'background-color': '#000', 'color': '#fff'});",
"}"),
columnDefs = list(list(targets = length(colnames(DF)), visible = TRUE)))) %>%

# Change fontsize of cell values
formatStyle(columns = c(1:length(colnames(df))),
fontSize = "85%",
fontFamily = "Verdana")%>%



# Format column based on P.Value levels
formatStyle(fontWeight = 'bold',
# Format this:
"PercentDone",

# Font color
color = styleInterval(c(0.0), c('black', 'black')),
backgroundColor = styleInterval(c(Threshold1, Threshold2),
c('lightgreen', '#f4d35e', "tomato"))) -> fancyTable


# Print customized color-coded datatable:
fancyTable






share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 19 at 11:51

























answered Nov 14 at 15:18









cgpu

263




263












  • I'd suggest uploading the image using StackOverflow's built-in system, especially if you are linking to someone else's dropbox. In the event the link goes dead.
    – Anonymous coward
    Nov 14 at 15:24






  • 1




    Thanks for your answer. I have moved on from this project in time, but I hope this may help someone in the future. Thanks again.
    – tsouchlarakis
    Nov 14 at 19:04










  • @Anonymouscoward Thanks for suggestion. I am new and posting a picture is not allowed unless one reaches a certain number of reputation points. Ideas on how to alt post an image very welcome
    – cgpu
    Nov 15 at 14:18


















  • I'd suggest uploading the image using StackOverflow's built-in system, especially if you are linking to someone else's dropbox. In the event the link goes dead.
    – Anonymous coward
    Nov 14 at 15:24






  • 1




    Thanks for your answer. I have moved on from this project in time, but I hope this may help someone in the future. Thanks again.
    – tsouchlarakis
    Nov 14 at 19:04










  • @Anonymouscoward Thanks for suggestion. I am new and posting a picture is not allowed unless one reaches a certain number of reputation points. Ideas on how to alt post an image very welcome
    – cgpu
    Nov 15 at 14:18
















I'd suggest uploading the image using StackOverflow's built-in system, especially if you are linking to someone else's dropbox. In the event the link goes dead.
– Anonymous coward
Nov 14 at 15:24




I'd suggest uploading the image using StackOverflow's built-in system, especially if you are linking to someone else's dropbox. In the event the link goes dead.
– Anonymous coward
Nov 14 at 15:24




1




1




Thanks for your answer. I have moved on from this project in time, but I hope this may help someone in the future. Thanks again.
– tsouchlarakis
Nov 14 at 19:04




Thanks for your answer. I have moved on from this project in time, but I hope this may help someone in the future. Thanks again.
– tsouchlarakis
Nov 14 at 19:04












@Anonymouscoward Thanks for suggestion. I am new and posting a picture is not allowed unless one reaches a certain number of reputation points. Ideas on how to alt post an image very welcome
– cgpu
Nov 15 at 14:18




@Anonymouscoward Thanks for suggestion. I am new and posting a picture is not allowed unless one reaches a certain number of reputation points. Ideas on how to alt post an image very welcome
– cgpu
Nov 15 at 14:18


















 

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