Number of oranges left [on hold]
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At a fruit stall, $40%$ of the fruits were oranges and the rest were apples. After some oranges were sold, the number of oranges became $20%$ of the total number of fruits remaining. There were $120$ apples and oranges at the fruit stall at first. How many oranges were sold?
How would I create an algebraic equation for this?
algebra-precalculus percentages word-problem
edited Nov 20 at 2:10
amWhy
191k27223437
asked Nov 20 at 2:00
RukaiPlusPlus
725
put on hold as off-topic by amWhy, Brahadeesh, max_zorn, KReiser, mau 2 days ago
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – amWhy, Brahadeesh, max_zorn, KReiser, mau
If this question can be reworded to fit the rules in the help center, please edit the question.
add a comment |
up vote
1
down vote
favorite
At a fruit stall, $40%$ of the fruits were oranges and the rest were apples. After some oranges were sold, the number of oranges became $20%$ of the total number of fruits remaining. There were $120$ apples and oranges at the fruit stall at first. How many oranges were sold?
How would I create an algebraic equation for this?
algebra-precalculus percentages word-problem
edited Nov 20 at 2:10
amWhy
191k27223437
asked Nov 20 at 2:00
RukaiPlusPlus
725
put on hold as off-topic by amWhy, Brahadeesh, max_zorn, KReiser, mau 2 days ago
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – amWhy, Brahadeesh, max_zorn, KReiser, mau
If this question can be reworded to fit the rules in the help center, please edit the question.
5
So, 40 % of the fruits were oranges, and 60% were apples. 120 apples and oranges. Meaning 0.4 (120)= 48 oranges, and 0.6(120) = 72 apples. Can you start with this information? Please show some work.
– amWhy
Nov 20 at 2:07
1
$48 text{ oranges} - x text{ oranges sold } = 20%$ of $120- x$ fruit remaining. $48 - x = 0.2cdot(120-x).$ Solve for $x$, the number of oranges sold
– amWhy
Nov 20 at 2:29
add a comment |
up vote
1
down vote
favorite
up vote
1
down vote
favorite
At a fruit stall, $40%$ of the fruits were oranges and the rest were apples. After some oranges were sold, the number of oranges became $20%$ of the total number of fruits remaining. There were $120$ apples and oranges at the fruit stall at first. How many oranges were sold?
How would I create an algebraic equation for this?
algebra-precalculus percentages word-problem
edited Nov 20 at 2:10
amWhy
191k27223437
asked Nov 20 at 2:00
RukaiPlusPlus
725
At a fruit stall, $40%$ of the fruits were oranges and the rest were apples. After some oranges were sold, the number of oranges became $20%$ of the total number of fruits remaining. There were $120$ apples and oranges at the fruit stall at first. How many oranges were sold?
How would I create an algebraic equation for this?
algebra-precalculus percentages word-problem
algebra-precalculus percentages word-problem
edited Nov 20 at 2:10
amWhy
191k27223437
asked Nov 20 at 2:00
RukaiPlusPlus
725
edited Nov 20 at 2:10
amWhy
191k27223437
asked Nov 20 at 2:00
RukaiPlusPlus
725
edited Nov 20 at 2:10
amWhy
191k27223437
edited Nov 20 at 2:10
amWhy
191k27223437
edited Nov 20 at 2:10
amWhy
191k27223437
191k27223437
asked Nov 20 at 2:00
RukaiPlusPlus
725
asked Nov 20 at 2:00
RukaiPlusPlus
725
asked Nov 20 at 2:00
RukaiPlusPlus
725
725
put on hold as off-topic by amWhy, Brahadeesh, max_zorn, KReiser, mau 2 days ago
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – amWhy, Brahadeesh, max_zorn, KReiser, mau
If this question can be reworded to fit the rules in the help center, please edit the question.
put on hold as off-topic by amWhy, Brahadeesh, max_zorn, KReiser, mau 2 days ago
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – amWhy, Brahadeesh, max_zorn, KReiser, mau
If this question can be reworded to fit the rules in the help center, please edit the question.
5
So, 40 % of the fruits were oranges, and 60% were apples. 120 apples and oranges. Meaning 0.4 (120)= 48 oranges, and 0.6(120) = 72 apples. Can you start with this information? Please show some work.
– amWhy
Nov 20 at 2:07
1
$48 text{ oranges} - x text{ oranges sold } = 20%$ of $120- x$ fruit remaining. $48 - x = 0.2cdot(120-x).$ Solve for $x$, the number of oranges sold
– amWhy
Nov 20 at 2:29
add a comment |
5
So, 40 % of the fruits were oranges, and 60% were apples. 120 apples and oranges. Meaning 0.4 (120)= 48 oranges, and 0.6(120) = 72 apples. Can you start with this information? Please show some work.
– amWhy
Nov 20 at 2:07
1
$48 text{ oranges} - x text{ oranges sold } = 20%$ of $120- x$ fruit remaining. $48 - x = 0.2cdot(120-x).$ Solve for $x$, the number of oranges sold
– amWhy
Nov 20 at 2:29
5
5
So, 40 % of the fruits were oranges, and 60% were apples. 120 apples and oranges. Meaning 0.4 (120)= 48 oranges, and 0.6(120) = 72 apples. Can you start with this information? Please show some work.
– amWhy
Nov 20 at 2:07
So, 40 % of the fruits were oranges, and 60% were apples. 120 apples and oranges. Meaning 0.4 (120)= 48 oranges, and 0.6(120) = 72 apples. Can you start with this information? Please show some work.
– amWhy
Nov 20 at 2:07
1
1
$48 text{ oranges} - x text{ oranges sold } = 20%$ of $120- x$ fruit remaining. $48 - x = 0.2cdot(120-x).$ Solve for $x$, the number of oranges sold
– amWhy
Nov 20 at 2:29
$48 text{ oranges} - x text{ oranges sold } = 20%$ of $120- x$ fruit remaining. $48 - x = 0.2cdot(120-x).$ Solve for $x$, the number of oranges sold
– amWhy
Nov 20 at 2:29
add a comment |
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5
So, 40 % of the fruits were oranges, and 60% were apples. 120 apples and oranges. Meaning 0.4 (120)= 48 oranges, and 0.6(120) = 72 apples. Can you start with this information? Please show some work.
– amWhy
Nov 20 at 2:07
1
$48 text{ oranges} - x text{ oranges sold } = 20%$ of $120- x$ fruit remaining. $48 - x = 0.2cdot(120-x).$ Solve for $x$, the number of oranges sold
– amWhy
Nov 20 at 2:29