Ytukyg

I have the following string format (Python 3.6):

'2018-11-19T10:04:57.426872'

I get it as a parameter to my script.
I want to get the date as 'YYYY-MM-DD' and time as 'HH:MM'

I tried to convert it with:

from datetime import datetime

if __name__ == '__main__':

    start_timestamp = sys.argv[1]

    start_date =  datetime.strptime(sys.argv[1], '%Y-%m-%d')

    start_time =  datetime.strptime(sys.argv[1], '%H:%M')

But this gives:

ValueError: unconverted data remains: T10:04:57.426872

In the above example I want to see:

start_date = '2018-11-19'

start_time = '10:04'

Since the date seems to be in ISO-Format, a simple

start = datetime.datetime.fromisoformat(text)

will parse it correctly. From there you can get your date and time with

start_date = start.strftime("%Y-%m-%d")

start_time = start.strftime("%H:%M")

Edit:

For Python < 3.7, you can use this format:

start = datetime.datetime.strptime(text, "%Y-%m-%dT%H:%M:%S.%f")

For the "duplicate" datetime confusion: I used import datetime. If you use from datetime import datetime, you can get rid of the additional datetime.

You need to parse the entire string into one datetime object and then extract your required values from that.

dt = datetime.datetime.strptime('2018-11-19T10:04:57.426872', '%Y-%m-%dT%H:%M:%S.%f')

d = dt.date()

t = dt.time()

print(d.strftime('%Y-%m-%d'))

print(t.strftime('%H:%M'))

Which outputs:

2018-11-19

10:04

Try this:We have one of the best package for parsing dates called dateutil.

from dateutil import parser

date1='2018-11-19T10:04:57.426872'

print 'Start_date:',parser.parse(date1).strftime("%Y-%m-%d") 

print 'Start_time:',parser.parse(date1).strftime("%H:%M")



Result:Start_date:2018-11-19

       Start_time:10:04