Express differential equation in matrix form
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Need help to the following question. Is there a way to express the following differential equation into a matrix form? Since there is a $sin(theta)$ term in the equation, how to handle this? Thanks in advance! Please consider $gamma = 7$.
$$ ddot{theta} + gammadot{theta} + sin(theta) = 0 tag{1} $$
given the conditions
$$ theta(0) = theta_{0} \ dot{theta}(0) = dot{theta}_{0} tag{2} $$
matrices differential-equations matrix-equations
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Need help to the following question. Is there a way to express the following differential equation into a matrix form? Since there is a $sin(theta)$ term in the equation, how to handle this? Thanks in advance! Please consider $gamma = 7$.
$$ ddot{theta} + gammadot{theta} + sin(theta) = 0 tag{1} $$
given the conditions
$$ theta(0) = theta_{0} \ dot{theta}(0) = dot{theta}_{0} tag{2} $$
matrices differential-equations matrix-equations
What is matrix form? If it is the usual $dot u=Au+b$, then it would imply that the equation were linear, which it obviously is not.
– LutzL
Nov 3 at 17:15
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up vote
1
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up vote
1
down vote
favorite
Need help to the following question. Is there a way to express the following differential equation into a matrix form? Since there is a $sin(theta)$ term in the equation, how to handle this? Thanks in advance! Please consider $gamma = 7$.
$$ ddot{theta} + gammadot{theta} + sin(theta) = 0 tag{1} $$
given the conditions
$$ theta(0) = theta_{0} \ dot{theta}(0) = dot{theta}_{0} tag{2} $$
matrices differential-equations matrix-equations
Need help to the following question. Is there a way to express the following differential equation into a matrix form? Since there is a $sin(theta)$ term in the equation, how to handle this? Thanks in advance! Please consider $gamma = 7$.
$$ ddot{theta} + gammadot{theta} + sin(theta) = 0 tag{1} $$
given the conditions
$$ theta(0) = theta_{0} \ dot{theta}(0) = dot{theta}_{0} tag{2} $$
matrices differential-equations matrix-equations
matrices differential-equations matrix-equations
edited Nov 3 at 17:11
Ryan Howe
2,38911323
2,38911323
asked Nov 3 at 16:57
Banana
63
63
What is matrix form? If it is the usual $dot u=Au+b$, then it would imply that the equation were linear, which it obviously is not.
– LutzL
Nov 3 at 17:15
add a comment |
What is matrix form? If it is the usual $dot u=Au+b$, then it would imply that the equation were linear, which it obviously is not.
– LutzL
Nov 3 at 17:15
What is matrix form? If it is the usual $dot u=Au+b$, then it would imply that the equation were linear, which it obviously is not.
– LutzL
Nov 3 at 17:15
What is matrix form? If it is the usual $dot u=Au+b$, then it would imply that the equation were linear, which it obviously is not.
– LutzL
Nov 3 at 17:15
add a comment |
1 Answer
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A matrix form, induces a linear matter inside the problem which is inapplicable to here since existence of $sin(.)$ term makes the problem generally non-linear regardless of initial conditions. Therefore a matrix form can be attained thereby tolerating errors. If we approximate $sin x$ with $x$ for small enough $x$ we obtain$$ddottheta+7dot theta+theta=0$$by defining state variables $theta_1=theta$ and $theta_2=dottheta$ we have$$begin{bmatrix}dottheta_1\dottheta_2end{bmatrix}=begin{bmatrix}0&1\-1&-7end{bmatrix}begin{bmatrix}theta_1\theta_2end{bmatrix}$$If we try to express the main problem we have$$begin{bmatrix}dottheta_1\dottheta_2end{bmatrix}=begin{bmatrix}0&1\-{sintheta_1over theta_1}&-7end{bmatrix}begin{bmatrix}theta_1\theta_2end{bmatrix}$$
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1 Answer
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
A matrix form, induces a linear matter inside the problem which is inapplicable to here since existence of $sin(.)$ term makes the problem generally non-linear regardless of initial conditions. Therefore a matrix form can be attained thereby tolerating errors. If we approximate $sin x$ with $x$ for small enough $x$ we obtain$$ddottheta+7dot theta+theta=0$$by defining state variables $theta_1=theta$ and $theta_2=dottheta$ we have$$begin{bmatrix}dottheta_1\dottheta_2end{bmatrix}=begin{bmatrix}0&1\-1&-7end{bmatrix}begin{bmatrix}theta_1\theta_2end{bmatrix}$$If we try to express the main problem we have$$begin{bmatrix}dottheta_1\dottheta_2end{bmatrix}=begin{bmatrix}0&1\-{sintheta_1over theta_1}&-7end{bmatrix}begin{bmatrix}theta_1\theta_2end{bmatrix}$$
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up vote
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A matrix form, induces a linear matter inside the problem which is inapplicable to here since existence of $sin(.)$ term makes the problem generally non-linear regardless of initial conditions. Therefore a matrix form can be attained thereby tolerating errors. If we approximate $sin x$ with $x$ for small enough $x$ we obtain$$ddottheta+7dot theta+theta=0$$by defining state variables $theta_1=theta$ and $theta_2=dottheta$ we have$$begin{bmatrix}dottheta_1\dottheta_2end{bmatrix}=begin{bmatrix}0&1\-1&-7end{bmatrix}begin{bmatrix}theta_1\theta_2end{bmatrix}$$If we try to express the main problem we have$$begin{bmatrix}dottheta_1\dottheta_2end{bmatrix}=begin{bmatrix}0&1\-{sintheta_1over theta_1}&-7end{bmatrix}begin{bmatrix}theta_1\theta_2end{bmatrix}$$
add a comment |
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up vote
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A matrix form, induces a linear matter inside the problem which is inapplicable to here since existence of $sin(.)$ term makes the problem generally non-linear regardless of initial conditions. Therefore a matrix form can be attained thereby tolerating errors. If we approximate $sin x$ with $x$ for small enough $x$ we obtain$$ddottheta+7dot theta+theta=0$$by defining state variables $theta_1=theta$ and $theta_2=dottheta$ we have$$begin{bmatrix}dottheta_1\dottheta_2end{bmatrix}=begin{bmatrix}0&1\-1&-7end{bmatrix}begin{bmatrix}theta_1\theta_2end{bmatrix}$$If we try to express the main problem we have$$begin{bmatrix}dottheta_1\dottheta_2end{bmatrix}=begin{bmatrix}0&1\-{sintheta_1over theta_1}&-7end{bmatrix}begin{bmatrix}theta_1\theta_2end{bmatrix}$$
A matrix form, induces a linear matter inside the problem which is inapplicable to here since existence of $sin(.)$ term makes the problem generally non-linear regardless of initial conditions. Therefore a matrix form can be attained thereby tolerating errors. If we approximate $sin x$ with $x$ for small enough $x$ we obtain$$ddottheta+7dot theta+theta=0$$by defining state variables $theta_1=theta$ and $theta_2=dottheta$ we have$$begin{bmatrix}dottheta_1\dottheta_2end{bmatrix}=begin{bmatrix}0&1\-1&-7end{bmatrix}begin{bmatrix}theta_1\theta_2end{bmatrix}$$If we try to express the main problem we have$$begin{bmatrix}dottheta_1\dottheta_2end{bmatrix}=begin{bmatrix}0&1\-{sintheta_1over theta_1}&-7end{bmatrix}begin{bmatrix}theta_1\theta_2end{bmatrix}$$
answered Nov 24 at 17:30
Mostafa Ayaz
13.4k3836
13.4k3836
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What is matrix form? If it is the usual $dot u=Au+b$, then it would imply that the equation were linear, which it obviously is not.
– LutzL
Nov 3 at 17:15