Convert bytes received by socket to float in Python 3











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I've tried following the suggested answer here but did not get the intended result:
Python Socket Received ASCII convert to actual numbers (float)



I'm receiving data in bytes format like so, using socket.recv():



      b'(1,3,-121.551552,-123.602531,-40.582172,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)'


I'm trying to receive the values above as a list of 30 floats.



I understand we have to use the struct library but I'm facing difficulties trying to grasp the concept of formatting.










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    up vote
    0
    down vote

    favorite












    I've tried following the suggested answer here but did not get the intended result:
    Python Socket Received ASCII convert to actual numbers (float)



    I'm receiving data in bytes format like so, using socket.recv():



          b'(1,3,-121.551552,-123.602531,-40.582172,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)'


    I'm trying to receive the values above as a list of 30 floats.



    I understand we have to use the struct library but I'm facing difficulties trying to grasp the concept of formatting.










    share|improve this question
























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      I've tried following the suggested answer here but did not get the intended result:
      Python Socket Received ASCII convert to actual numbers (float)



      I'm receiving data in bytes format like so, using socket.recv():



            b'(1,3,-121.551552,-123.602531,-40.582172,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)'


      I'm trying to receive the values above as a list of 30 floats.



      I understand we have to use the struct library but I'm facing difficulties trying to grasp the concept of formatting.










      share|improve this question













      I've tried following the suggested answer here but did not get the intended result:
      Python Socket Received ASCII convert to actual numbers (float)



      I'm receiving data in bytes format like so, using socket.recv():



            b'(1,3,-121.551552,-123.602531,-40.582172,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)'


      I'm trying to receive the values above as a list of 30 floats.



      I understand we have to use the struct library but I'm facing difficulties trying to grasp the concept of formatting.







      python struct byte ascii






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      asked Nov 20 at 4:14









      Maximilian Tan

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          Your incoming floats aren't fixed-length, apart from having 6 decimal paces, if at all. So why not just use bytes.decode(), then strip off the brackets and then split on commas?



          With each step broken down:



          >>> b = b'(1,3,-121.551552,-123.602531,-40.582172,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)'
          >>> b.decode()
          '(1,3,-121.551552,-123.602531,-40.582172,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)'
          >>> b.decode()[1:-1]
          '1,3,-121.551552,-123.602531,-40.582172,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0'
          >>> b.decode()[1:-1].split(',')
          ['1', '3', '-121.551552', '-123.602531', '-40.582172', '0', '0', '0', '0', '0', '0', '0',
          '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0']
          >>> [float(x) for x in b.decode()[1:-1].split(',')]
          [1.0, 3.0, -121.551552, -123.602531, -40.582172, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0,
          0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0,
          0.0, 0.0, 0.0, 0.0]


          And a more Pythonic way to do that last one-step:



          >>> list(map(float, b.decode()[1:-1].split(',')))
          [1.0, 3.0, -121.551552, -123.602531, -40.582172, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0,
          0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0]





          share|improve this answer























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            1 Answer
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            1 Answer
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            up vote
            0
            down vote













            Your incoming floats aren't fixed-length, apart from having 6 decimal paces, if at all. So why not just use bytes.decode(), then strip off the brackets and then split on commas?



            With each step broken down:



            >>> b = b'(1,3,-121.551552,-123.602531,-40.582172,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)'
            >>> b.decode()
            '(1,3,-121.551552,-123.602531,-40.582172,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)'
            >>> b.decode()[1:-1]
            '1,3,-121.551552,-123.602531,-40.582172,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0'
            >>> b.decode()[1:-1].split(',')
            ['1', '3', '-121.551552', '-123.602531', '-40.582172', '0', '0', '0', '0', '0', '0', '0',
            '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0']
            >>> [float(x) for x in b.decode()[1:-1].split(',')]
            [1.0, 3.0, -121.551552, -123.602531, -40.582172, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0,
            0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0,
            0.0, 0.0, 0.0, 0.0]


            And a more Pythonic way to do that last one-step:



            >>> list(map(float, b.decode()[1:-1].split(',')))
            [1.0, 3.0, -121.551552, -123.602531, -40.582172, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0,
            0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0]





            share|improve this answer



























              up vote
              0
              down vote













              Your incoming floats aren't fixed-length, apart from having 6 decimal paces, if at all. So why not just use bytes.decode(), then strip off the brackets and then split on commas?



              With each step broken down:



              >>> b = b'(1,3,-121.551552,-123.602531,-40.582172,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)'
              >>> b.decode()
              '(1,3,-121.551552,-123.602531,-40.582172,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)'
              >>> b.decode()[1:-1]
              '1,3,-121.551552,-123.602531,-40.582172,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0'
              >>> b.decode()[1:-1].split(',')
              ['1', '3', '-121.551552', '-123.602531', '-40.582172', '0', '0', '0', '0', '0', '0', '0',
              '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0']
              >>> [float(x) for x in b.decode()[1:-1].split(',')]
              [1.0, 3.0, -121.551552, -123.602531, -40.582172, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0,
              0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0,
              0.0, 0.0, 0.0, 0.0]


              And a more Pythonic way to do that last one-step:



              >>> list(map(float, b.decode()[1:-1].split(',')))
              [1.0, 3.0, -121.551552, -123.602531, -40.582172, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0,
              0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0]





              share|improve this answer

























                up vote
                0
                down vote










                up vote
                0
                down vote









                Your incoming floats aren't fixed-length, apart from having 6 decimal paces, if at all. So why not just use bytes.decode(), then strip off the brackets and then split on commas?



                With each step broken down:



                >>> b = b'(1,3,-121.551552,-123.602531,-40.582172,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)'
                >>> b.decode()
                '(1,3,-121.551552,-123.602531,-40.582172,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)'
                >>> b.decode()[1:-1]
                '1,3,-121.551552,-123.602531,-40.582172,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0'
                >>> b.decode()[1:-1].split(',')
                ['1', '3', '-121.551552', '-123.602531', '-40.582172', '0', '0', '0', '0', '0', '0', '0',
                '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0']
                >>> [float(x) for x in b.decode()[1:-1].split(',')]
                [1.0, 3.0, -121.551552, -123.602531, -40.582172, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0,
                0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0,
                0.0, 0.0, 0.0, 0.0]


                And a more Pythonic way to do that last one-step:



                >>> list(map(float, b.decode()[1:-1].split(',')))
                [1.0, 3.0, -121.551552, -123.602531, -40.582172, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0,
                0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0]





                share|improve this answer














                Your incoming floats aren't fixed-length, apart from having 6 decimal paces, if at all. So why not just use bytes.decode(), then strip off the brackets and then split on commas?



                With each step broken down:



                >>> b = b'(1,3,-121.551552,-123.602531,-40.582172,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)'
                >>> b.decode()
                '(1,3,-121.551552,-123.602531,-40.582172,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)'
                >>> b.decode()[1:-1]
                '1,3,-121.551552,-123.602531,-40.582172,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0'
                >>> b.decode()[1:-1].split(',')
                ['1', '3', '-121.551552', '-123.602531', '-40.582172', '0', '0', '0', '0', '0', '0', '0',
                '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0']
                >>> [float(x) for x in b.decode()[1:-1].split(',')]
                [1.0, 3.0, -121.551552, -123.602531, -40.582172, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0,
                0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0,
                0.0, 0.0, 0.0, 0.0]


                And a more Pythonic way to do that last one-step:



                >>> list(map(float, b.decode()[1:-1].split(',')))
                [1.0, 3.0, -121.551552, -123.602531, -40.582172, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0,
                0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0]






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                edited Nov 20 at 4:35

























                answered Nov 20 at 4:26









                aneroid

                6,93522542




                6,93522542






























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