Convert bytes received by socket to float in Python 3
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I've tried following the suggested answer here but did not get the intended result:
Python Socket Received ASCII convert to actual numbers (float)
I'm receiving data in bytes format like so, using socket.recv():
b'(1,3,-121.551552,-123.602531,-40.582172,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)'
I'm trying to receive the values above as a list of 30 floats.
I understand we have to use the struct library but I'm facing difficulties trying to grasp the concept of formatting.
python struct byte ascii
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up vote
0
down vote
favorite
I've tried following the suggested answer here but did not get the intended result:
Python Socket Received ASCII convert to actual numbers (float)
I'm receiving data in bytes format like so, using socket.recv():
b'(1,3,-121.551552,-123.602531,-40.582172,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)'
I'm trying to receive the values above as a list of 30 floats.
I understand we have to use the struct library but I'm facing difficulties trying to grasp the concept of formatting.
python struct byte ascii
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I've tried following the suggested answer here but did not get the intended result:
Python Socket Received ASCII convert to actual numbers (float)
I'm receiving data in bytes format like so, using socket.recv():
b'(1,3,-121.551552,-123.602531,-40.582172,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)'
I'm trying to receive the values above as a list of 30 floats.
I understand we have to use the struct library but I'm facing difficulties trying to grasp the concept of formatting.
python struct byte ascii
I've tried following the suggested answer here but did not get the intended result:
Python Socket Received ASCII convert to actual numbers (float)
I'm receiving data in bytes format like so, using socket.recv():
b'(1,3,-121.551552,-123.602531,-40.582172,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)'
I'm trying to receive the values above as a list of 30 floats.
I understand we have to use the struct library but I'm facing difficulties trying to grasp the concept of formatting.
python struct byte ascii
python struct byte ascii
asked Nov 20 at 4:14
Maximilian Tan
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1
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1 Answer
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Your incoming floats aren't fixed-length, apart from having 6 decimal paces, if at all. So why not just use bytes.decode()
, then strip off the brackets and then split on commas?
With each step broken down:
>>> b = b'(1,3,-121.551552,-123.602531,-40.582172,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)'
>>> b.decode()
'(1,3,-121.551552,-123.602531,-40.582172,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)'
>>> b.decode()[1:-1]
'1,3,-121.551552,-123.602531,-40.582172,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0'
>>> b.decode()[1:-1].split(',')
['1', '3', '-121.551552', '-123.602531', '-40.582172', '0', '0', '0', '0', '0', '0', '0',
'0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0']
>>> [float(x) for x in b.decode()[1:-1].split(',')]
[1.0, 3.0, -121.551552, -123.602531, -40.582172, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0,
0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0,
0.0, 0.0, 0.0, 0.0]
And a more Pythonic way to do that last one-step:
>>> list(map(float, b.decode()[1:-1].split(',')))
[1.0, 3.0, -121.551552, -123.602531, -40.582172, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0,
0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0]
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
Your incoming floats aren't fixed-length, apart from having 6 decimal paces, if at all. So why not just use bytes.decode()
, then strip off the brackets and then split on commas?
With each step broken down:
>>> b = b'(1,3,-121.551552,-123.602531,-40.582172,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)'
>>> b.decode()
'(1,3,-121.551552,-123.602531,-40.582172,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)'
>>> b.decode()[1:-1]
'1,3,-121.551552,-123.602531,-40.582172,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0'
>>> b.decode()[1:-1].split(',')
['1', '3', '-121.551552', '-123.602531', '-40.582172', '0', '0', '0', '0', '0', '0', '0',
'0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0']
>>> [float(x) for x in b.decode()[1:-1].split(',')]
[1.0, 3.0, -121.551552, -123.602531, -40.582172, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0,
0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0,
0.0, 0.0, 0.0, 0.0]
And a more Pythonic way to do that last one-step:
>>> list(map(float, b.decode()[1:-1].split(',')))
[1.0, 3.0, -121.551552, -123.602531, -40.582172, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0,
0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0]
add a comment |
up vote
0
down vote
Your incoming floats aren't fixed-length, apart from having 6 decimal paces, if at all. So why not just use bytes.decode()
, then strip off the brackets and then split on commas?
With each step broken down:
>>> b = b'(1,3,-121.551552,-123.602531,-40.582172,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)'
>>> b.decode()
'(1,3,-121.551552,-123.602531,-40.582172,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)'
>>> b.decode()[1:-1]
'1,3,-121.551552,-123.602531,-40.582172,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0'
>>> b.decode()[1:-1].split(',')
['1', '3', '-121.551552', '-123.602531', '-40.582172', '0', '0', '0', '0', '0', '0', '0',
'0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0']
>>> [float(x) for x in b.decode()[1:-1].split(',')]
[1.0, 3.0, -121.551552, -123.602531, -40.582172, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0,
0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0,
0.0, 0.0, 0.0, 0.0]
And a more Pythonic way to do that last one-step:
>>> list(map(float, b.decode()[1:-1].split(',')))
[1.0, 3.0, -121.551552, -123.602531, -40.582172, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0,
0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0]
add a comment |
up vote
0
down vote
up vote
0
down vote
Your incoming floats aren't fixed-length, apart from having 6 decimal paces, if at all. So why not just use bytes.decode()
, then strip off the brackets and then split on commas?
With each step broken down:
>>> b = b'(1,3,-121.551552,-123.602531,-40.582172,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)'
>>> b.decode()
'(1,3,-121.551552,-123.602531,-40.582172,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)'
>>> b.decode()[1:-1]
'1,3,-121.551552,-123.602531,-40.582172,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0'
>>> b.decode()[1:-1].split(',')
['1', '3', '-121.551552', '-123.602531', '-40.582172', '0', '0', '0', '0', '0', '0', '0',
'0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0']
>>> [float(x) for x in b.decode()[1:-1].split(',')]
[1.0, 3.0, -121.551552, -123.602531, -40.582172, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0,
0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0,
0.0, 0.0, 0.0, 0.0]
And a more Pythonic way to do that last one-step:
>>> list(map(float, b.decode()[1:-1].split(',')))
[1.0, 3.0, -121.551552, -123.602531, -40.582172, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0,
0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0]
Your incoming floats aren't fixed-length, apart from having 6 decimal paces, if at all. So why not just use bytes.decode()
, then strip off the brackets and then split on commas?
With each step broken down:
>>> b = b'(1,3,-121.551552,-123.602531,-40.582172,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)'
>>> b.decode()
'(1,3,-121.551552,-123.602531,-40.582172,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)'
>>> b.decode()[1:-1]
'1,3,-121.551552,-123.602531,-40.582172,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0'
>>> b.decode()[1:-1].split(',')
['1', '3', '-121.551552', '-123.602531', '-40.582172', '0', '0', '0', '0', '0', '0', '0',
'0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0']
>>> [float(x) for x in b.decode()[1:-1].split(',')]
[1.0, 3.0, -121.551552, -123.602531, -40.582172, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0,
0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0,
0.0, 0.0, 0.0, 0.0]
And a more Pythonic way to do that last one-step:
>>> list(map(float, b.decode()[1:-1].split(',')))
[1.0, 3.0, -121.551552, -123.602531, -40.582172, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0,
0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0]
edited Nov 20 at 4:35
answered Nov 20 at 4:26
aneroid
6,93522542
6,93522542
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