Why isn't socket unlinked / removed after the process exits?












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If I bind and listen to a TCP port, the 'bind' is freed when my program exits.
If I bind and listen to a unix domain socket, the socket remains and the next time my program can't bind the socket. Why is this?
Should I manually unlink the socket before binding?
What if I don't want to disturb an existing instance of my program using the socket?










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    0















    If I bind and listen to a TCP port, the 'bind' is freed when my program exits.
    If I bind and listen to a unix domain socket, the socket remains and the next time my program can't bind the socket. Why is this?
    Should I manually unlink the socket before binding?
    What if I don't want to disturb an existing instance of my program using the socket?










    share|improve this question

























      0












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      0








      If I bind and listen to a TCP port, the 'bind' is freed when my program exits.
      If I bind and listen to a unix domain socket, the socket remains and the next time my program can't bind the socket. Why is this?
      Should I manually unlink the socket before binding?
      What if I don't want to disturb an existing instance of my program using the socket?










      share|improve this question














      If I bind and listen to a TCP port, the 'bind' is freed when my program exits.
      If I bind and listen to a unix domain socket, the socket remains and the next time my program can't bind the socket. Why is this?
      Should I manually unlink the socket before binding?
      What if I don't want to disturb an existing instance of my program using the socket?







      linux unix-domain-sockets






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 23 '18 at 14:04









      XTFXTF

      491520




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