Classification theorem of topological vector bundles via presheaves











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My issue is mainly set theoretical:

In "Dale Husemoller: Fiber Bundles" it says on page 34 that there is a cofunctor $Vekt_{k}: Prightarrow ens$, where $P$ is the category of paracompact spaces with homotopy classes of maps and ens the category of sets and functions, assigning to each paracompact space $B$ the set of $B$-isomorphism classes of vector bundles over $B$.

Unfortunately,I don't have any profound knowledge of set theory and I do not understand why this actually forms a set and not a proper class. Can anyone help me with this?










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    up vote
    1
    down vote

    favorite












    My issue is mainly set theoretical:

    In "Dale Husemoller: Fiber Bundles" it says on page 34 that there is a cofunctor $Vekt_{k}: Prightarrow ens$, where $P$ is the category of paracompact spaces with homotopy classes of maps and ens the category of sets and functions, assigning to each paracompact space $B$ the set of $B$-isomorphism classes of vector bundles over $B$.

    Unfortunately,I don't have any profound knowledge of set theory and I do not understand why this actually forms a set and not a proper class. Can anyone help me with this?










    share|cite|improve this question
























      up vote
      1
      down vote

      favorite









      up vote
      1
      down vote

      favorite











      My issue is mainly set theoretical:

      In "Dale Husemoller: Fiber Bundles" it says on page 34 that there is a cofunctor $Vekt_{k}: Prightarrow ens$, where $P$ is the category of paracompact spaces with homotopy classes of maps and ens the category of sets and functions, assigning to each paracompact space $B$ the set of $B$-isomorphism classes of vector bundles over $B$.

      Unfortunately,I don't have any profound knowledge of set theory and I do not understand why this actually forms a set and not a proper class. Can anyone help me with this?










      share|cite|improve this question













      My issue is mainly set theoretical:

      In "Dale Husemoller: Fiber Bundles" it says on page 34 that there is a cofunctor $Vekt_{k}: Prightarrow ens$, where $P$ is the category of paracompact spaces with homotopy classes of maps and ens the category of sets and functions, assigning to each paracompact space $B$ the set of $B$-isomorphism classes of vector bundles over $B$.

      Unfortunately,I don't have any profound knowledge of set theory and I do not understand why this actually forms a set and not a proper class. Can anyone help me with this?







      algebraic-topology category-theory set-theory vector-bundles






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      asked Nov 20 at 14:47









      Joo

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          I assumed your vector bundles are finite-dimensional, because the isomorphism classes of infinite-dimensional vector bundles never form a set-not even over a point! Given that, the key point is that (real or complex) vector bundles over $B$ have bounded cardinality: their underlying sets cannot be larger than the maximum of the cardinality of $mathbb{R}$ and the cardinality of the base space. There are only a set worth of isomorphism classes of triples $(E,T,f)$ where $E$ is a set of bounded cardinality, $T$ is a topology on $E$, and $f$ is a continuous function $Eto B$. Indeed, we could assume that $E$ is always a subset of some fixed set by applying an appropriate isomorphism. The set of isomorphism classes of vector bundles is a subset of this set.






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            I assumed your vector bundles are finite-dimensional, because the isomorphism classes of infinite-dimensional vector bundles never form a set-not even over a point! Given that, the key point is that (real or complex) vector bundles over $B$ have bounded cardinality: their underlying sets cannot be larger than the maximum of the cardinality of $mathbb{R}$ and the cardinality of the base space. There are only a set worth of isomorphism classes of triples $(E,T,f)$ where $E$ is a set of bounded cardinality, $T$ is a topology on $E$, and $f$ is a continuous function $Eto B$. Indeed, we could assume that $E$ is always a subset of some fixed set by applying an appropriate isomorphism. The set of isomorphism classes of vector bundles is a subset of this set.






            share|cite|improve this answer

























              up vote
              4
              down vote



              accepted










              I assumed your vector bundles are finite-dimensional, because the isomorphism classes of infinite-dimensional vector bundles never form a set-not even over a point! Given that, the key point is that (real or complex) vector bundles over $B$ have bounded cardinality: their underlying sets cannot be larger than the maximum of the cardinality of $mathbb{R}$ and the cardinality of the base space. There are only a set worth of isomorphism classes of triples $(E,T,f)$ where $E$ is a set of bounded cardinality, $T$ is a topology on $E$, and $f$ is a continuous function $Eto B$. Indeed, we could assume that $E$ is always a subset of some fixed set by applying an appropriate isomorphism. The set of isomorphism classes of vector bundles is a subset of this set.






              share|cite|improve this answer























                up vote
                4
                down vote



                accepted







                up vote
                4
                down vote



                accepted






                I assumed your vector bundles are finite-dimensional, because the isomorphism classes of infinite-dimensional vector bundles never form a set-not even over a point! Given that, the key point is that (real or complex) vector bundles over $B$ have bounded cardinality: their underlying sets cannot be larger than the maximum of the cardinality of $mathbb{R}$ and the cardinality of the base space. There are only a set worth of isomorphism classes of triples $(E,T,f)$ where $E$ is a set of bounded cardinality, $T$ is a topology on $E$, and $f$ is a continuous function $Eto B$. Indeed, we could assume that $E$ is always a subset of some fixed set by applying an appropriate isomorphism. The set of isomorphism classes of vector bundles is a subset of this set.






                share|cite|improve this answer












                I assumed your vector bundles are finite-dimensional, because the isomorphism classes of infinite-dimensional vector bundles never form a set-not even over a point! Given that, the key point is that (real or complex) vector bundles over $B$ have bounded cardinality: their underlying sets cannot be larger than the maximum of the cardinality of $mathbb{R}$ and the cardinality of the base space. There are only a set worth of isomorphism classes of triples $(E,T,f)$ where $E$ is a set of bounded cardinality, $T$ is a topology on $E$, and $f$ is a continuous function $Eto B$. Indeed, we could assume that $E$ is always a subset of some fixed set by applying an appropriate isomorphism. The set of isomorphism classes of vector bundles is a subset of this set.







                share|cite|improve this answer












                share|cite|improve this answer



                share|cite|improve this answer










                answered Nov 20 at 17:20









                Kevin Carlson

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