Is there explicit solution for this integral? [on hold]
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How we can calculate the indefinite integral
$int (x^a-y^a)^{-1/a} dy?$
Or can we find the simpler upper bound for this integral?
calculus
edited Nov 20 at 14:56
saulspatz
12.9k21327
asked Nov 20 at 14:43
Mathlove
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put on hold as off-topic by Winther, Rebellos, KReiser, jgon, Cesareo Nov 21 at 2:14
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Winther, Rebellos, KReiser, jgon, Cesareo
If this question can be reworded to fit the rules in the help center, please edit the question.
add a comment |
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How we can calculate the indefinite integral
$int (x^a-y^a)^{-1/a} dy?$
Or can we find the simpler upper bound for this integral?
calculus
edited Nov 20 at 14:56
saulspatz
12.9k21327
asked Nov 20 at 14:43
Mathlove
1
New contributor
Mathlove is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
put on hold as off-topic by Winther, Rebellos, KReiser, jgon, Cesareo Nov 21 at 2:14
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Winther, Rebellos, KReiser, jgon, Cesareo
If this question can be reworded to fit the rules in the help center, please edit the question.
2
It does not make much sense to talk about an upper bound for an indefinite integral.
– Winther
Nov 20 at 15:08
You can express it as an incomplete $beta$ integral (unless the bounds are $0$ to $x$). en.wikipedia.org/wiki/Beta_function#Incomplete_beta_function
– Yves Daoust
Nov 20 at 15:08
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
How we can calculate the indefinite integral
$int (x^a-y^a)^{-1/a} dy?$
Or can we find the simpler upper bound for this integral?
calculus
edited Nov 20 at 14:56
saulspatz
12.9k21327
asked Nov 20 at 14:43
Mathlove
1
New contributor
Mathlove is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
How we can calculate the indefinite integral
$int (x^a-y^a)^{-1/a} dy?$
Or can we find the simpler upper bound for this integral?
calculus
calculus
edited Nov 20 at 14:56
saulspatz
12.9k21327
asked Nov 20 at 14:43
Mathlove
1
New contributor
Mathlove is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited Nov 20 at 14:56
saulspatz
12.9k21327
asked Nov 20 at 14:43
Mathlove
1
New contributor
Mathlove is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited Nov 20 at 14:56
saulspatz
12.9k21327
edited Nov 20 at 14:56
saulspatz
12.9k21327
edited Nov 20 at 14:56
saulspatz
12.9k21327
12.9k21327
asked Nov 20 at 14:43
Mathlove
1
New contributor
Mathlove is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Nov 20 at 14:43
Mathlove
1
asked Nov 20 at 14:43
Mathlove
1
1
New contributor
Mathlove is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Mathlove is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Mathlove is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
put on hold as off-topic by Winther, Rebellos, KReiser, jgon, Cesareo Nov 21 at 2:14
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Winther, Rebellos, KReiser, jgon, Cesareo
If this question can be reworded to fit the rules in the help center, please edit the question.
put on hold as off-topic by Winther, Rebellos, KReiser, jgon, Cesareo Nov 21 at 2:14
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Winther, Rebellos, KReiser, jgon, Cesareo
If this question can be reworded to fit the rules in the help center, please edit the question.
2
It does not make much sense to talk about an upper bound for an indefinite integral.
– Winther
Nov 20 at 15:08
You can express it as an incomplete $beta$ integral (unless the bounds are $0$ to $x$). en.wikipedia.org/wiki/Beta_function#Incomplete_beta_function
– Yves Daoust
Nov 20 at 15:08
add a comment |
2
It does not make much sense to talk about an upper bound for an indefinite integral.
– Winther
Nov 20 at 15:08
You can express it as an incomplete $beta$ integral (unless the bounds are $0$ to $x$). en.wikipedia.org/wiki/Beta_function#Incomplete_beta_function
– Yves Daoust
Nov 20 at 15:08
2
2
It does not make much sense to talk about an upper bound for an indefinite integral.
– Winther
Nov 20 at 15:08
It does not make much sense to talk about an upper bound for an indefinite integral.
– Winther
Nov 20 at 15:08
You can express it as an incomplete $beta$ integral (unless the bounds are $0$ to $x$). en.wikipedia.org/wiki/Beta_function#Incomplete_beta_function
– Yves Daoust
Nov 20 at 15:08
You can express it as an incomplete $beta$ integral (unless the bounds are $0$ to $x$). en.wikipedia.org/wiki/Beta_function#Incomplete_beta_function
– Yves Daoust
Nov 20 at 15:08
add a comment |
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2
It does not make much sense to talk about an upper bound for an indefinite integral.
– Winther
Nov 20 at 15:08
You can express it as an incomplete $beta$ integral (unless the bounds are $0$ to $x$). en.wikipedia.org/wiki/Beta_function#Incomplete_beta_function
– Yves Daoust
Nov 20 at 15:08