convert SELECT query from mySql to Laravel query builder
what would be Laravel Query Builder code of this mysql query;
SELECT *
FROM Student
WHERE family_id IN (SELECT family_id
FROM students
GROUP BY family_id
HAVING COUNT(1)>1)
ORDER BY family_id
mysql laravel
add a comment |
what would be Laravel Query Builder code of this mysql query;
SELECT *
FROM Student
WHERE family_id IN (SELECT family_id
FROM students
GROUP BY family_id
HAVING COUNT(1)>1)
ORDER BY family_id
mysql laravel
I recommend you to use Eloquen Models. Check out the docs
– Pepe
Nov 24 '18 at 2:22
add a comment |
what would be Laravel Query Builder code of this mysql query;
SELECT *
FROM Student
WHERE family_id IN (SELECT family_id
FROM students
GROUP BY family_id
HAVING COUNT(1)>1)
ORDER BY family_id
mysql laravel
what would be Laravel Query Builder code of this mysql query;
SELECT *
FROM Student
WHERE family_id IN (SELECT family_id
FROM students
GROUP BY family_id
HAVING COUNT(1)>1)
ORDER BY family_id
mysql laravel
mysql laravel
asked Nov 23 '18 at 23:52
iscpreeeiscpreee
133
133
I recommend you to use Eloquen Models. Check out the docs
– Pepe
Nov 24 '18 at 2:22
add a comment |
I recommend you to use Eloquen Models. Check out the docs
– Pepe
Nov 24 '18 at 2:22
I recommend you to use Eloquen Models. Check out the docs
– Pepe
Nov 24 '18 at 2:22
I recommend you to use Eloquen Models. Check out the docs
– Pepe
Nov 24 '18 at 2:22
add a comment |
2 Answers
2
active
oldest
votes
$query = DB::select("SELECT *
FROM Student
WHERE family_id IN (SELECT family_id
FROM students
GROUP BY family_id
HAVING COUNT(1)>1)
ORDER BY family_id")
Based on Laravel Documentation
add a comment |
Use function in whereIn clause:
Student::whereIn('family_id', function($query) {
$query->select('family_id')
->from(with(new Students)->getTable())
->groupBy('family_id')
->havingRaw('COUNT(1) > 1')
})->get();
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$query = DB::select("SELECT *
FROM Student
WHERE family_id IN (SELECT family_id
FROM students
GROUP BY family_id
HAVING COUNT(1)>1)
ORDER BY family_id")
Based on Laravel Documentation
add a comment |
$query = DB::select("SELECT *
FROM Student
WHERE family_id IN (SELECT family_id
FROM students
GROUP BY family_id
HAVING COUNT(1)>1)
ORDER BY family_id")
Based on Laravel Documentation
add a comment |
$query = DB::select("SELECT *
FROM Student
WHERE family_id IN (SELECT family_id
FROM students
GROUP BY family_id
HAVING COUNT(1)>1)
ORDER BY family_id")
Based on Laravel Documentation
$query = DB::select("SELECT *
FROM Student
WHERE family_id IN (SELECT family_id
FROM students
GROUP BY family_id
HAVING COUNT(1)>1)
ORDER BY family_id")
Based on Laravel Documentation
answered Nov 24 '18 at 1:41
KelvinKelvin
413324
413324
add a comment |
add a comment |
Use function in whereIn clause:
Student::whereIn('family_id', function($query) {
$query->select('family_id')
->from(with(new Students)->getTable())
->groupBy('family_id')
->havingRaw('COUNT(1) > 1')
})->get();
add a comment |
Use function in whereIn clause:
Student::whereIn('family_id', function($query) {
$query->select('family_id')
->from(with(new Students)->getTable())
->groupBy('family_id')
->havingRaw('COUNT(1) > 1')
})->get();
add a comment |
Use function in whereIn clause:
Student::whereIn('family_id', function($query) {
$query->select('family_id')
->from(with(new Students)->getTable())
->groupBy('family_id')
->havingRaw('COUNT(1) > 1')
})->get();
Use function in whereIn clause:
Student::whereIn('family_id', function($query) {
$query->select('family_id')
->from(with(new Students)->getTable())
->groupBy('family_id')
->havingRaw('COUNT(1) > 1')
})->get();
answered Nov 24 '18 at 4:10
Dhruv RavalDhruv Raval
1,066312
1,066312
add a comment |
add a comment |
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I recommend you to use Eloquen Models. Check out the docs
– Pepe
Nov 24 '18 at 2:22