How can I remove time from date with Moment.js?

181

formatCalendarDate = function (dateTime) {

    return moment.utc(dateTime).format('LLL');

};

It displays: "28 februari 2013 09:24"

But I would like to remove the time at the end. How can I do that?

I'm using Moment.js.

edited May 23 '17 at 8:11

Pang

6,8911563101

asked Feb 28 '13 at 8:25

Obsivus

3,398103990

Use Split method to separate the strings

– AmGates
Feb 28 '13 at 8:28

add a comment |

181

formatCalendarDate = function (dateTime) {

    return moment.utc(dateTime).format('LLL');

};

It displays: "28 februari 2013 09:24"

But I would like to remove the time at the end. How can I do that?

I'm using Moment.js.

edited May 23 '17 at 8:11

Pang

6,8911563101

asked Feb 28 '13 at 8:25

Obsivus

3,398103990

Use Split method to separate the strings

– AmGates
Feb 28 '13 at 8:28

add a comment |

181

formatCalendarDate = function (dateTime) {

    return moment.utc(dateTime).format('LLL');

};

It displays: "28 februari 2013 09:24"

But I would like to remove the time at the end. How can I do that?

I'm using Moment.js.

edited May 23 '17 at 8:11

Pang

6,8911563101

asked Feb 28 '13 at 8:25

Obsivus

3,398103990

formatCalendarDate = function (dateTime) {

    return moment.utc(dateTime).format('LLL');

};

It displays: "28 februari 2013 09:24"

But I would like to remove the time at the end. How can I do that?

I'm using Moment.js.

javascript date momentjs

edited May 23 '17 at 8:11

Pang

6,8911563101

asked Feb 28 '13 at 8:25

Obsivus

3,398103990

edited May 23 '17 at 8:11

Pang

6,8911563101

asked Feb 28 '13 at 8:25

Obsivus

3,398103990

edited May 23 '17 at 8:11

Pang

6,8911563101

edited May 23 '17 at 8:11

Pang

6,8911563101

edited May 23 '17 at 8:11

Pang

6,8911563101

asked Feb 28 '13 at 8:25

Obsivus

3,398103990

asked Feb 28 '13 at 8:25

Obsivus

3,398103990

asked Feb 28 '13 at 8:25

Obsivus

3,398103990

Use Split method to separate the strings

– AmGates
Feb 28 '13 at 8:28

add a comment |

Use Split method to separate the strings

– AmGates
Feb 28 '13 at 8:28

Use Split method to separate the strings

– AmGates
Feb 28 '13 at 8:28

add a comment |

10 Answers
10

active

oldest

votes

456

Sorry to jump in so late, but if you want to remove the time portion of a moment() rather than formatting it, then the code is:

.startOf('day')

Ref: http://momentjs.com/docs/#/manipulating/start-of/

edited Nov 26 '18 at 16:18

trojek

676730

answered Oct 31 '13 at 6:03

Graham Charles

5,53132035

66

Be careful with this if you're going between timezones (or if you're not paying attention to timezones). I had an issue where my UTC date was getting converted to local time, then applying startOf('day'), which was then the start of the previous day. Fixed with moment(moment.utc('2013-10-29T00:00:00+00:00').startOf('day').format('LL')).startOf('day').toDate()

– colllin
Nov 6 '13 at 5:37

6

This should definetly be the accepted answer

– Luca Steeb
Apr 23 '15 at 20:03

19

Also be careful that this function actually mutates the original object

– Dirk Boer
Jul 8 '15 at 16:36

4

.startOf('day') does not removes the time part per se, it just sets the time to 00:00:00. So, yes, as commented by 'collin', you have to be careful when saving date. Better alternative is using format('LL'), as have been answered in this thread.

– Sudarshan_SMD
Dec 13 '16 at 7:18

2

To avoid mutating the original object, use someMoment.clone().startOf('day') or moment(someMoment).startOf('day').

– Pang
May 23 '17 at 8:06

|
show 3 more comments

Use `format('LL')`

Depending on what you're trying to do with it, format('LL') could do the trick. It produces something like this:

Moment().format('LL'); // => April 29, 2016

edited May 21 '18 at 16:53

answered Apr 30 '16 at 0:52

Joshua Pinter

24.1k8138165

add a comment |

The correct way would be to specify the input as per your requirement which will give you more flexibility.

The present definition includes the following

LTS : 'h:mm:ss A', LT : 'h:mm A', L : 'MM/DD/YYYY', LL : 'MMMM D, YYYY', LLL : 'MMMM D, YYYY h:mm A', LLLL : 'dddd, MMMM D, YYYY h:mm A'

You can use any of these or change the input passed into moment().format().
For example, for your case you can pass moment.utc(dateTime).format('MMMM D, YYYY').

answered Mar 1 '17 at 17:07

Sahil Jain

7111614

add a comment |

formatCalendarDate = function (dateTime) {

    return moment.utc(dateTime).format('LL')

}

edited May 23 '17 at 8:13

Pang

6,8911563101

answered Feb 28 '13 at 8:31

AmGates

1,6881326

add a comment |

You can also use this format:

moment().format('ddd, ll'); // Wed, Jan 4, 2017

answered Jan 4 '17 at 7:54

Hashmita Raut

516

add a comment |

With newer versions of moment.js you can also do this:

var dateTime = moment();



var dateValue = moment({

    year: dateTime.year(),

    month: dateTime.month(),

    day: dateTime.date()

});

See: http://momentjs.com/docs/#/parsing/object/.

edited Feb 2 '18 at 17:59

FlavorScape

5,02665493

answered Sep 10 '15 at 16:52

Torben Rahbek Koch

582314

Wouldn't it be date: dateTime.date() instead of day: dateTime.date()?

– philfreo
Oct 26 '16 at 18:44

'day and date key both mean day-of-the-month.' from the docs. day works pre version 2.8.4.

– oldwizard
May 17 '17 at 7:13

add a comment |

You can use this constructor

moment({h:0, m:0, s:0, ms:0})

http://momentjs.com/docs/#/parsing/object/

console.log( moment().format('YYYY-MM-DD HH:mm:ss') )



console.log( moment({h:0, m:0, s:0, ms:0}).format('YYYY-MM-DD HH:mm:ss') )

<script src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.22.2/moment.min.js"></script>

edited Nov 21 '18 at 22:34

answered Aug 23 '18 at 12:29

EquaPro

3195

Add some ore description here

– Billa
Aug 23 '18 at 12:45

add a comment |

Try this:

moment.format().split("T")[0]

edited Aug 28 '17 at 23:19

Moe A

3,75371227

answered Aug 28 '17 at 22:59

Keith Blanchard

111

Watch out with this method, as 1993-06-07T22:00:00.000Z will result as 1993-06-07 whereas it is the start of the day of 1993-06-08

– Tom
Nov 20 '17 at 7:49

add a comment |

Whenever I use the moment.js library I specify the desired format this way:

moment(<your Date goes here>).format("DD-MMM-YYYY")

moment(<your Date goes here>).format("DD/MMM/YYYY")

... etc I hope you get the idea

Inside the format function, you put the desired format. The example above will get rid of all unwanted elements from the date such as minutes and seconds

answered Oct 16 '17 at 9:42

Adrian Grzywaczewski

3651314

This is not a good idea if you ever want to display your content in different locales. If you want to display dates in the correct format for the user's locale, you need to use one of the preset date formats (L, LL, etc.)

– AJ Richardson
Apr 2 '18 at 21:46

add a comment |

For people like me want the long date format (LLLL) but without the time of day, there's a GitHub issue for that: https://github.com/moment/moment/issues/2505. For now, there's a workaround:

var localeData = moment.localeData( moment.locale() ),

    llll = localeData.longDateFormat( 'llll' ),

    lll = localeData.longDateFormat( 'lll' ),

    ll = localeData.longDateFormat( 'll' ),

    longDateFormat = llll.replace( lll.replace( ll, '' ), '' );

var formattedDate = myMoment.format(longDateFormat);

answered Apr 2 '18 at 21:58

AJ Richardson

4,1372948

add a comment |

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10 Answers
10

active

oldest

votes

10 Answers
10

active

oldest

votes

456

Sorry to jump in so late, but if you want to remove the time portion of a moment() rather than formatting it, then the code is:

.startOf('day')

Ref: http://momentjs.com/docs/#/manipulating/start-of/

edited Nov 26 '18 at 16:18

trojek

676730

answered Oct 31 '13 at 6:03

Graham Charles

5,53132035

66

Be careful with this if you're going between timezones (or if you're not paying attention to timezones). I had an issue where my UTC date was getting converted to local time, then applying startOf('day'), which was then the start of the previous day. Fixed with moment(moment.utc('2013-10-29T00:00:00+00:00').startOf('day').format('LL')).startOf('day').toDate()

– colllin
Nov 6 '13 at 5:37

6

This should definetly be the accepted answer

– Luca Steeb
Apr 23 '15 at 20:03

19

Also be careful that this function actually mutates the original object

– Dirk Boer
Jul 8 '15 at 16:36

4

.startOf('day') does not removes the time part per se, it just sets the time to 00:00:00. So, yes, as commented by 'collin', you have to be careful when saving date. Better alternative is using format('LL'), as have been answered in this thread.

– Sudarshan_SMD
Dec 13 '16 at 7:18

2

To avoid mutating the original object, use someMoment.clone().startOf('day') or moment(someMoment).startOf('day').

– Pang
May 23 '17 at 8:06

|
show 3 more comments

456

Sorry to jump in so late, but if you want to remove the time portion of a moment() rather than formatting it, then the code is:

.startOf('day')

Ref: http://momentjs.com/docs/#/manipulating/start-of/

edited Nov 26 '18 at 16:18

trojek

676730

answered Oct 31 '13 at 6:03

Graham Charles

5,53132035

66

Be careful with this if you're going between timezones (or if you're not paying attention to timezones). I had an issue where my UTC date was getting converted to local time, then applying startOf('day'), which was then the start of the previous day. Fixed with moment(moment.utc('2013-10-29T00:00:00+00:00').startOf('day').format('LL')).startOf('day').toDate()

– colllin
Nov 6 '13 at 5:37

6

This should definetly be the accepted answer

– Luca Steeb
Apr 23 '15 at 20:03

19

Also be careful that this function actually mutates the original object

– Dirk Boer
Jul 8 '15 at 16:36

4

.startOf('day') does not removes the time part per se, it just sets the time to 00:00:00. So, yes, as commented by 'collin', you have to be careful when saving date. Better alternative is using format('LL'), as have been answered in this thread.

– Sudarshan_SMD
Dec 13 '16 at 7:18

2

To avoid mutating the original object, use someMoment.clone().startOf('day') or moment(someMoment).startOf('day').

– Pang
May 23 '17 at 8:06

|
show 3 more comments

456

Sorry to jump in so late, but if you want to remove the time portion of a moment() rather than formatting it, then the code is:

.startOf('day')

Ref: http://momentjs.com/docs/#/manipulating/start-of/

edited Nov 26 '18 at 16:18

trojek

676730

answered Oct 31 '13 at 6:03

Graham Charles

5,53132035

Sorry to jump in so late, but if you want to remove the time portion of a moment() rather than formatting it, then the code is:

.startOf('day')

Ref: http://momentjs.com/docs/#/manipulating/start-of/

edited Nov 26 '18 at 16:18

trojek

676730

answered Oct 31 '13 at 6:03

Graham Charles

5,53132035

edited Nov 26 '18 at 16:18

trojek

676730

edited Nov 26 '18 at 16:18

trojek

676730

edited Nov 26 '18 at 16:18

trojek

676730

answered Oct 31 '13 at 6:03

Graham Charles

5,53132035

answered Oct 31 '13 at 6:03

Graham Charles

5,53132035

answered Oct 31 '13 at 6:03

Graham Charles

5,53132035

66

Be careful with this if you're going between timezones (or if you're not paying attention to timezones). I had an issue where my UTC date was getting converted to local time, then applying startOf('day'), which was then the start of the previous day. Fixed with moment(moment.utc('2013-10-29T00:00:00+00:00').startOf('day').format('LL')).startOf('day').toDate()

– colllin
Nov 6 '13 at 5:37

6

This should definetly be the accepted answer

– Luca Steeb
Apr 23 '15 at 20:03

19

Also be careful that this function actually mutates the original object

– Dirk Boer
Jul 8 '15 at 16:36

4

.startOf('day') does not removes the time part per se, it just sets the time to 00:00:00. So, yes, as commented by 'collin', you have to be careful when saving date. Better alternative is using format('LL'), as have been answered in this thread.

– Sudarshan_SMD
Dec 13 '16 at 7:18

2

To avoid mutating the original object, use someMoment.clone().startOf('day') or moment(someMoment).startOf('day').

– Pang
May 23 '17 at 8:06

|
show 3 more comments

66

Be careful with this if you're going between timezones (or if you're not paying attention to timezones). I had an issue where my UTC date was getting converted to local time, then applying startOf('day'), which was then the start of the previous day. Fixed with moment(moment.utc('2013-10-29T00:00:00+00:00').startOf('day').format('LL')).startOf('day').toDate()

– colllin
Nov 6 '13 at 5:37

6

This should definetly be the accepted answer

– Luca Steeb
Apr 23 '15 at 20:03

19

Also be careful that this function actually mutates the original object

– Dirk Boer
Jul 8 '15 at 16:36

4

.startOf('day') does not removes the time part per se, it just sets the time to 00:00:00. So, yes, as commented by 'collin', you have to be careful when saving date. Better alternative is using format('LL'), as have been answered in this thread.

– Sudarshan_SMD
Dec 13 '16 at 7:18

2

To avoid mutating the original object, use someMoment.clone().startOf('day') or moment(someMoment).startOf('day').

– Pang
May 23 '17 at 8:06

Be careful with this if you're going between timezones (or if you're not paying attention to timezones). I had an issue where my UTC date was getting converted to local time, then applying startOf('day'), which was then the start of the previous day. Fixed with moment(moment.utc('2013-10-29T00:00:00+00:00').startOf('day').format('LL')).startOf('day').toDate()

– colllin
Nov 6 '13 at 5:37

This should definetly be the accepted answer

– Luca Steeb
Apr 23 '15 at 20:03

Also be careful that this function actually mutates the original object

– Dirk Boer
Jul 8 '15 at 16:36

.startOf('day') does not removes the time part per se, it just sets the time to 00:00:00. So, yes, as commented by 'collin', you have to be careful when saving date. Better alternative is using format('LL'), as have been answered in this thread.

– Sudarshan_SMD
Dec 13 '16 at 7:18

To avoid mutating the original object, use someMoment.clone().startOf('day') or moment(someMoment).startOf('day').

– Pang
May 23 '17 at 8:06

|
show 3 more comments

Use `format('LL')`

Depending on what you're trying to do with it, format('LL') could do the trick. It produces something like this:

Moment().format('LL'); // => April 29, 2016

edited May 21 '18 at 16:53

answered Apr 30 '16 at 0:52

Joshua Pinter

24.1k8138165

add a comment |

Use `format('LL')`

Depending on what you're trying to do with it, format('LL') could do the trick. It produces something like this:

Moment().format('LL'); // => April 29, 2016

edited May 21 '18 at 16:53

answered Apr 30 '16 at 0:52

Joshua Pinter

24.1k8138165

add a comment |

Use `format('LL')`

Depending on what you're trying to do with it, format('LL') could do the trick. It produces something like this:

Moment().format('LL'); // => April 29, 2016

edited May 21 '18 at 16:53

answered Apr 30 '16 at 0:52

Joshua Pinter

24.1k8138165

Use `format('LL')`

Depending on what you're trying to do with it, format('LL') could do the trick. It produces something like this:

Moment().format('LL'); // => April 29, 2016

edited May 21 '18 at 16:53

answered Apr 30 '16 at 0:52

Joshua Pinter

24.1k8138165

edited May 21 '18 at 16:53

answered Apr 30 '16 at 0:52

Joshua Pinter

24.1k8138165

answered Apr 30 '16 at 0:52

Joshua Pinter

24.1k8138165

answered Apr 30 '16 at 0:52

Joshua Pinter

24.1k8138165

add a comment |

The correct way would be to specify the input as per your requirement which will give you more flexibility.

The present definition includes the following

LTS : 'h:mm:ss A', LT : 'h:mm A', L : 'MM/DD/YYYY', LL : 'MMMM D, YYYY', LLL : 'MMMM D, YYYY h:mm A', LLLL : 'dddd, MMMM D, YYYY h:mm A'

You can use any of these or change the input passed into moment().format().
For example, for your case you can pass moment.utc(dateTime).format('MMMM D, YYYY').

answered Mar 1 '17 at 17:07

Sahil Jain

7111614

add a comment |

The correct way would be to specify the input as per your requirement which will give you more flexibility.

The present definition includes the following

LTS : 'h:mm:ss A', LT : 'h:mm A', L : 'MM/DD/YYYY', LL : 'MMMM D, YYYY', LLL : 'MMMM D, YYYY h:mm A', LLLL : 'dddd, MMMM D, YYYY h:mm A'

You can use any of these or change the input passed into moment().format().
For example, for your case you can pass moment.utc(dateTime).format('MMMM D, YYYY').

answered Mar 1 '17 at 17:07

Sahil Jain

7111614

add a comment |

The correct way would be to specify the input as per your requirement which will give you more flexibility.

The present definition includes the following

LTS : 'h:mm:ss A', LT : 'h:mm A', L : 'MM/DD/YYYY', LL : 'MMMM D, YYYY', LLL : 'MMMM D, YYYY h:mm A', LLLL : 'dddd, MMMM D, YYYY h:mm A'

You can use any of these or change the input passed into moment().format().
For example, for your case you can pass moment.utc(dateTime).format('MMMM D, YYYY').

answered Mar 1 '17 at 17:07

Sahil Jain

7111614

The correct way would be to specify the input as per your requirement which will give you more flexibility.

The present definition includes the following

LTS : 'h:mm:ss A', LT : 'h:mm A', L : 'MM/DD/YYYY', LL : 'MMMM D, YYYY', LLL : 'MMMM D, YYYY h:mm A', LLLL : 'dddd, MMMM D, YYYY h:mm A'

You can use any of these or change the input passed into moment().format().
For example, for your case you can pass moment.utc(dateTime).format('MMMM D, YYYY').

answered Mar 1 '17 at 17:07

Sahil Jain

7111614

answered Mar 1 '17 at 17:07

Sahil Jain

7111614

answered Mar 1 '17 at 17:07

Sahil Jain

7111614

answered Mar 1 '17 at 17:07

Sahil Jain

7111614

add a comment |

formatCalendarDate = function (dateTime) {

    return moment.utc(dateTime).format('LL')

}

edited May 23 '17 at 8:13

Pang

6,8911563101

answered Feb 28 '13 at 8:31

AmGates

1,6881326

add a comment |

formatCalendarDate = function (dateTime) {

    return moment.utc(dateTime).format('LL')

}

edited May 23 '17 at 8:13

Pang

6,8911563101

answered Feb 28 '13 at 8:31

AmGates

1,6881326

add a comment |

formatCalendarDate = function (dateTime) {

    return moment.utc(dateTime).format('LL')

}

edited May 23 '17 at 8:13

Pang

6,8911563101

answered Feb 28 '13 at 8:31

AmGates

1,6881326

formatCalendarDate = function (dateTime) {

    return moment.utc(dateTime).format('LL')

}

edited May 23 '17 at 8:13

Pang

6,8911563101

answered Feb 28 '13 at 8:31

AmGates

1,6881326

edited May 23 '17 at 8:13

Pang

6,8911563101

edited May 23 '17 at 8:13

Pang

6,8911563101

edited May 23 '17 at 8:13

Pang

6,8911563101

answered Feb 28 '13 at 8:31

AmGates

1,6881326

answered Feb 28 '13 at 8:31

AmGates

1,6881326

answered Feb 28 '13 at 8:31

AmGates

1,6881326

add a comment |

You can also use this format:

moment().format('ddd, ll'); // Wed, Jan 4, 2017

answered Jan 4 '17 at 7:54

Hashmita Raut

516

add a comment |

You can also use this format:

moment().format('ddd, ll'); // Wed, Jan 4, 2017

answered Jan 4 '17 at 7:54

Hashmita Raut

516

add a comment |

You can also use this format:

moment().format('ddd, ll'); // Wed, Jan 4, 2017

answered Jan 4 '17 at 7:54

Hashmita Raut

516

You can also use this format:

moment().format('ddd, ll'); // Wed, Jan 4, 2017

answered Jan 4 '17 at 7:54

Hashmita Raut

516

answered Jan 4 '17 at 7:54

Hashmita Raut

516

answered Jan 4 '17 at 7:54

Hashmita Raut

516

answered Jan 4 '17 at 7:54

Hashmita Raut

516

add a comment |

With newer versions of moment.js you can also do this:

var dateTime = moment();



var dateValue = moment({

    year: dateTime.year(),

    month: dateTime.month(),

    day: dateTime.date()

});

See: http://momentjs.com/docs/#/parsing/object/.

edited Feb 2 '18 at 17:59

FlavorScape

5,02665493

answered Sep 10 '15 at 16:52

Torben Rahbek Koch

582314

Wouldn't it be date: dateTime.date() instead of day: dateTime.date()?

– philfreo
Oct 26 '16 at 18:44

'day and date key both mean day-of-the-month.' from the docs. day works pre version 2.8.4.

– oldwizard
May 17 '17 at 7:13

add a comment |

With newer versions of moment.js you can also do this:

var dateTime = moment();



var dateValue = moment({

    year: dateTime.year(),

    month: dateTime.month(),

    day: dateTime.date()

});

See: http://momentjs.com/docs/#/parsing/object/.

edited Feb 2 '18 at 17:59

FlavorScape

5,02665493

answered Sep 10 '15 at 16:52

Torben Rahbek Koch

582314

Wouldn't it be date: dateTime.date() instead of day: dateTime.date()?

– philfreo
Oct 26 '16 at 18:44

'day and date key both mean day-of-the-month.' from the docs. day works pre version 2.8.4.

– oldwizard
May 17 '17 at 7:13

add a comment |

With newer versions of moment.js you can also do this:

var dateTime = moment();



var dateValue = moment({

    year: dateTime.year(),

    month: dateTime.month(),

    day: dateTime.date()

});

See: http://momentjs.com/docs/#/parsing/object/.

edited Feb 2 '18 at 17:59

FlavorScape

5,02665493

answered Sep 10 '15 at 16:52

Torben Rahbek Koch

582314

With newer versions of moment.js you can also do this:

var dateTime = moment();



var dateValue = moment({

    year: dateTime.year(),

    month: dateTime.month(),

    day: dateTime.date()

});

See: http://momentjs.com/docs/#/parsing/object/.

edited Feb 2 '18 at 17:59

FlavorScape

5,02665493

answered Sep 10 '15 at 16:52

Torben Rahbek Koch

582314

edited Feb 2 '18 at 17:59

FlavorScape

5,02665493

edited Feb 2 '18 at 17:59

FlavorScape

5,02665493

edited Feb 2 '18 at 17:59

FlavorScape

5,02665493

answered Sep 10 '15 at 16:52

Torben Rahbek Koch

582314

answered Sep 10 '15 at 16:52

Torben Rahbek Koch

582314

answered Sep 10 '15 at 16:52

Torben Rahbek Koch

582314

Wouldn't it be date: dateTime.date() instead of day: dateTime.date()?

– philfreo
Oct 26 '16 at 18:44

'day and date key both mean day-of-the-month.' from the docs. day works pre version 2.8.4.

– oldwizard
May 17 '17 at 7:13

add a comment |

Wouldn't it be date: dateTime.date() instead of day: dateTime.date()?

– philfreo
Oct 26 '16 at 18:44

'day and date key both mean day-of-the-month.' from the docs. day works pre version 2.8.4.

– oldwizard
May 17 '17 at 7:13

Wouldn't it be date: dateTime.date() instead of day: dateTime.date()?

– philfreo
Oct 26 '16 at 18:44

'day and date key both mean day-of-the-month.' from the docs. day works pre version 2.8.4.

– oldwizard
May 17 '17 at 7:13

add a comment |

You can use this constructor

moment({h:0, m:0, s:0, ms:0})

http://momentjs.com/docs/#/parsing/object/

console.log( moment().format('YYYY-MM-DD HH:mm:ss') )



console.log( moment({h:0, m:0, s:0, ms:0}).format('YYYY-MM-DD HH:mm:ss') )

<script src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.22.2/moment.min.js"></script>

edited Nov 21 '18 at 22:34

answered Aug 23 '18 at 12:29

EquaPro

3195

Add some ore description here

– Billa
Aug 23 '18 at 12:45

add a comment |

You can use this constructor

moment({h:0, m:0, s:0, ms:0})

http://momentjs.com/docs/#/parsing/object/

console.log( moment().format('YYYY-MM-DD HH:mm:ss') )



console.log( moment({h:0, m:0, s:0, ms:0}).format('YYYY-MM-DD HH:mm:ss') )

<script src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.22.2/moment.min.js"></script>

edited Nov 21 '18 at 22:34

answered Aug 23 '18 at 12:29

EquaPro

3195

Add some ore description here

– Billa
Aug 23 '18 at 12:45

add a comment |

You can use this constructor

moment({h:0, m:0, s:0, ms:0})

http://momentjs.com/docs/#/parsing/object/

console.log( moment().format('YYYY-MM-DD HH:mm:ss') )



console.log( moment({h:0, m:0, s:0, ms:0}).format('YYYY-MM-DD HH:mm:ss') )

<script src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.22.2/moment.min.js"></script>

edited Nov 21 '18 at 22:34

answered Aug 23 '18 at 12:29

EquaPro

3195

You can use this constructor

moment({h:0, m:0, s:0, ms:0})

http://momentjs.com/docs/#/parsing/object/

console.log( moment().format('YYYY-MM-DD HH:mm:ss') )



console.log( moment({h:0, m:0, s:0, ms:0}).format('YYYY-MM-DD HH:mm:ss') )

<script src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.22.2/moment.min.js"></script>

console.log( moment().format('YYYY-MM-DD HH:mm:ss') )



console.log( moment({h:0, m:0, s:0, ms:0}).format('YYYY-MM-DD HH:mm:ss') )

<script src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.22.2/moment.min.js"></script>

console.log( moment().format('YYYY-MM-DD HH:mm:ss') )



console.log( moment({h:0, m:0, s:0, ms:0}).format('YYYY-MM-DD HH:mm:ss') )

<script src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.22.2/moment.min.js"></script>

edited Nov 21 '18 at 22:34

answered Aug 23 '18 at 12:29

EquaPro

3195

edited Nov 21 '18 at 22:34

answered Aug 23 '18 at 12:29

EquaPro

3195

answered Aug 23 '18 at 12:29

EquaPro

3195

answered Aug 23 '18 at 12:29

EquaPro

3195

Add some ore description here

– Billa
Aug 23 '18 at 12:45

add a comment |

Add some ore description here

– Billa
Aug 23 '18 at 12:45

Add some ore description here

– Billa
Aug 23 '18 at 12:45

add a comment |

Try this:

moment.format().split("T")[0]

edited Aug 28 '17 at 23:19

Moe A

3,75371227

answered Aug 28 '17 at 22:59

Keith Blanchard

111

Watch out with this method, as 1993-06-07T22:00:00.000Z will result as 1993-06-07 whereas it is the start of the day of 1993-06-08

– Tom
Nov 20 '17 at 7:49

add a comment |

Try this:

moment.format().split("T")[0]

edited Aug 28 '17 at 23:19

Moe A

3,75371227

answered Aug 28 '17 at 22:59

Keith Blanchard

111

Watch out with this method, as 1993-06-07T22:00:00.000Z will result as 1993-06-07 whereas it is the start of the day of 1993-06-08

– Tom
Nov 20 '17 at 7:49

add a comment |

Try this:

moment.format().split("T")[0]

edited Aug 28 '17 at 23:19

Moe A

3,75371227

answered Aug 28 '17 at 22:59

Keith Blanchard

111

Try this:

moment.format().split("T")[0]

edited Aug 28 '17 at 23:19

Moe A

3,75371227

answered Aug 28 '17 at 22:59

Keith Blanchard

111

edited Aug 28 '17 at 23:19

Moe A

3,75371227

edited Aug 28 '17 at 23:19

Moe A

3,75371227

edited Aug 28 '17 at 23:19

Moe A

3,75371227

answered Aug 28 '17 at 22:59

Keith Blanchard

111

answered Aug 28 '17 at 22:59

Keith Blanchard

111

answered Aug 28 '17 at 22:59

Keith Blanchard

111

Watch out with this method, as 1993-06-07T22:00:00.000Z will result as 1993-06-07 whereas it is the start of the day of 1993-06-08

– Tom
Nov 20 '17 at 7:49

add a comment |

Watch out with this method, as 1993-06-07T22:00:00.000Z will result as 1993-06-07 whereas it is the start of the day of 1993-06-08

– Tom
Nov 20 '17 at 7:49

Watch out with this method, as 1993-06-07T22:00:00.000Z will result as 1993-06-07 whereas it is the start of the day of 1993-06-08

– Tom
Nov 20 '17 at 7:49

add a comment |

Whenever I use the moment.js library I specify the desired format this way:

moment(<your Date goes here>).format("DD-MMM-YYYY")

moment(<your Date goes here>).format("DD/MMM/YYYY")

... etc I hope you get the idea

Inside the format function, you put the desired format. The example above will get rid of all unwanted elements from the date such as minutes and seconds

answered Oct 16 '17 at 9:42

Adrian Grzywaczewski

3651314

This is not a good idea if you ever want to display your content in different locales. If you want to display dates in the correct format for the user's locale, you need to use one of the preset date formats (L, LL, etc.)

– AJ Richardson
Apr 2 '18 at 21:46

add a comment |

Whenever I use the moment.js library I specify the desired format this way:

moment(<your Date goes here>).format("DD-MMM-YYYY")

moment(<your Date goes here>).format("DD/MMM/YYYY")

... etc I hope you get the idea

Inside the format function, you put the desired format. The example above will get rid of all unwanted elements from the date such as minutes and seconds

answered Oct 16 '17 at 9:42

Adrian Grzywaczewski

3651314

This is not a good idea if you ever want to display your content in different locales. If you want to display dates in the correct format for the user's locale, you need to use one of the preset date formats (L, LL, etc.)

– AJ Richardson
Apr 2 '18 at 21:46

add a comment |

Whenever I use the moment.js library I specify the desired format this way:

moment(<your Date goes here>).format("DD-MMM-YYYY")

moment(<your Date goes here>).format("DD/MMM/YYYY")

... etc I hope you get the idea

Inside the format function, you put the desired format. The example above will get rid of all unwanted elements from the date such as minutes and seconds

answered Oct 16 '17 at 9:42

Adrian Grzywaczewski

3651314

Whenever I use the moment.js library I specify the desired format this way:

moment(<your Date goes here>).format("DD-MMM-YYYY")

moment(<your Date goes here>).format("DD/MMM/YYYY")

... etc I hope you get the idea

Inside the format function, you put the desired format. The example above will get rid of all unwanted elements from the date such as minutes and seconds

answered Oct 16 '17 at 9:42

Adrian Grzywaczewski

3651314

answered Oct 16 '17 at 9:42

Adrian Grzywaczewski

3651314

answered Oct 16 '17 at 9:42

Adrian Grzywaczewski

3651314

answered Oct 16 '17 at 9:42

Adrian Grzywaczewski

3651314

This is not a good idea if you ever want to display your content in different locales. If you want to display dates in the correct format for the user's locale, you need to use one of the preset date formats (L, LL, etc.)

– AJ Richardson
Apr 2 '18 at 21:46

add a comment |

This is not a good idea if you ever want to display your content in different locales. If you want to display dates in the correct format for the user's locale, you need to use one of the preset date formats (L, LL, etc.)

– AJ Richardson
Apr 2 '18 at 21:46

This is not a good idea if you ever want to display your content in different locales. If you want to display dates in the correct format for the user's locale, you need to use one of the preset date formats (L, LL, etc.)

– AJ Richardson
Apr 2 '18 at 21:46

add a comment |

For people like me want the long date format (LLLL) but without the time of day, there's a GitHub issue for that: https://github.com/moment/moment/issues/2505. For now, there's a workaround:

var localeData = moment.localeData( moment.locale() ),

    llll = localeData.longDateFormat( 'llll' ),

    lll = localeData.longDateFormat( 'lll' ),

    ll = localeData.longDateFormat( 'll' ),

    longDateFormat = llll.replace( lll.replace( ll, '' ), '' );

var formattedDate = myMoment.format(longDateFormat);

answered Apr 2 '18 at 21:58

AJ Richardson

4,1372948

add a comment |

For people like me want the long date format (LLLL) but without the time of day, there's a GitHub issue for that: https://github.com/moment/moment/issues/2505. For now, there's a workaround:

var localeData = moment.localeData( moment.locale() ),

    llll = localeData.longDateFormat( 'llll' ),

    lll = localeData.longDateFormat( 'lll' ),

    ll = localeData.longDateFormat( 'll' ),

    longDateFormat = llll.replace( lll.replace( ll, '' ), '' );

var formattedDate = myMoment.format(longDateFormat);

answered Apr 2 '18 at 21:58

AJ Richardson

4,1372948

add a comment |

For people like me want the long date format (LLLL) but without the time of day, there's a GitHub issue for that: https://github.com/moment/moment/issues/2505. For now, there's a workaround:

var localeData = moment.localeData( moment.locale() ),

    llll = localeData.longDateFormat( 'llll' ),

    lll = localeData.longDateFormat( 'lll' ),

    ll = localeData.longDateFormat( 'll' ),

    longDateFormat = llll.replace( lll.replace( ll, '' ), '' );

var formattedDate = myMoment.format(longDateFormat);

answered Apr 2 '18 at 21:58

AJ Richardson

4,1372948

For people like me want the long date format (LLLL) but without the time of day, there's a GitHub issue for that: https://github.com/moment/moment/issues/2505. For now, there's a workaround:

var localeData = moment.localeData( moment.locale() ),

    llll = localeData.longDateFormat( 'llll' ),

    lll = localeData.longDateFormat( 'lll' ),

    ll = localeData.longDateFormat( 'll' ),

    longDateFormat = llll.replace( lll.replace( ll, '' ), '' );

var formattedDate = myMoment.format(longDateFormat);

answered Apr 2 '18 at 21:58

AJ Richardson

4,1372948

answered Apr 2 '18 at 21:58

AJ Richardson

4,1372948

answered Apr 2 '18 at 21:58

AJ Richardson

4,1372948

answered Apr 2 '18 at 21:58

AJ Richardson

4,1372948

add a comment |

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