query results with hibernate-search with associated enumeration field
I am trying to make document index of the Entity that has following associations:
DocVersion:
@Entity
@Indexed
public class DocVersion implements Serializable {
...
@ManyToOne(fetch = FetchType.EAGER, cascade = CascadeType.ALL)
@JoinColumn(name = "doc_uuid")
@IndexedEmbedded
private Document2 document2;
...
}
Document2:
@Entity
@Indexed
public class Document2 implements Serializable {
...
@Column(name = "entityState")
@Enumerated(EnumType.STRING)
@Field(bridge=@FieldBridge(impl=EnumBridge.class), index=Index.YES)
private EDocState eDocState;
...
}
this is how I query the index (just for testing purposes):
FullTextEntityManager fullTextEntityManager = Search.getFullTextEntityManager(entityManager);
try {
fullTextEntityManager.createIndexer().startAndWait();
} catch (InterruptedException e) {
e.printStackTrace();
}
QueryBuilder queryBuilder = fullTextEntityManager.getSearchFactory()
.buildQueryBuilder()
.forEntity(DocVersion.class)
.get();
org.apache.lucene.search.Query luceneQuery = queryBuilder.keyword()
.onField("document2.eDocState").matching("HARD_DEL")
.createQuery();
List results = fullTextEntityManager.createFullTextQuery(luceneQuery, DocVersion.class)
.getResultList();
but instead of results I get:
WARNING: org.hibernate.search.bridge.BridgeException: Exception while calling bridge#objectToString
entity class: com.nws.vedica.model.entity.DocVersion
entity property path: document2.eDocState
field bridge: TwoWayString2FieldBridgeAdaptor [stringBridge=org.hibernate.search.bridge.builtin.EnumBridge@60942b8b]
So what does that mean? Do I need to implement some specific bridge for an Enumeration (how would that look like)?
It's just value enum so I think problem is somewhere else.
Please assist me to get the results.
package I'm using:
hibernate-search-orm: 5.9.3.
java lucene hibernate-search
add a comment |
I am trying to make document index of the Entity that has following associations:
DocVersion:
@Entity
@Indexed
public class DocVersion implements Serializable {
...
@ManyToOne(fetch = FetchType.EAGER, cascade = CascadeType.ALL)
@JoinColumn(name = "doc_uuid")
@IndexedEmbedded
private Document2 document2;
...
}
Document2:
@Entity
@Indexed
public class Document2 implements Serializable {
...
@Column(name = "entityState")
@Enumerated(EnumType.STRING)
@Field(bridge=@FieldBridge(impl=EnumBridge.class), index=Index.YES)
private EDocState eDocState;
...
}
this is how I query the index (just for testing purposes):
FullTextEntityManager fullTextEntityManager = Search.getFullTextEntityManager(entityManager);
try {
fullTextEntityManager.createIndexer().startAndWait();
} catch (InterruptedException e) {
e.printStackTrace();
}
QueryBuilder queryBuilder = fullTextEntityManager.getSearchFactory()
.buildQueryBuilder()
.forEntity(DocVersion.class)
.get();
org.apache.lucene.search.Query luceneQuery = queryBuilder.keyword()
.onField("document2.eDocState").matching("HARD_DEL")
.createQuery();
List results = fullTextEntityManager.createFullTextQuery(luceneQuery, DocVersion.class)
.getResultList();
but instead of results I get:
WARNING: org.hibernate.search.bridge.BridgeException: Exception while calling bridge#objectToString
entity class: com.nws.vedica.model.entity.DocVersion
entity property path: document2.eDocState
field bridge: TwoWayString2FieldBridgeAdaptor [stringBridge=org.hibernate.search.bridge.builtin.EnumBridge@60942b8b]
So what does that mean? Do I need to implement some specific bridge for an Enumeration (how would that look like)?
It's just value enum so I think problem is somewhere else.
Please assist me to get the results.
package I'm using:
hibernate-search-orm: 5.9.3.
java lucene hibernate-search
add a comment |
I am trying to make document index of the Entity that has following associations:
DocVersion:
@Entity
@Indexed
public class DocVersion implements Serializable {
...
@ManyToOne(fetch = FetchType.EAGER, cascade = CascadeType.ALL)
@JoinColumn(name = "doc_uuid")
@IndexedEmbedded
private Document2 document2;
...
}
Document2:
@Entity
@Indexed
public class Document2 implements Serializable {
...
@Column(name = "entityState")
@Enumerated(EnumType.STRING)
@Field(bridge=@FieldBridge(impl=EnumBridge.class), index=Index.YES)
private EDocState eDocState;
...
}
this is how I query the index (just for testing purposes):
FullTextEntityManager fullTextEntityManager = Search.getFullTextEntityManager(entityManager);
try {
fullTextEntityManager.createIndexer().startAndWait();
} catch (InterruptedException e) {
e.printStackTrace();
}
QueryBuilder queryBuilder = fullTextEntityManager.getSearchFactory()
.buildQueryBuilder()
.forEntity(DocVersion.class)
.get();
org.apache.lucene.search.Query luceneQuery = queryBuilder.keyword()
.onField("document2.eDocState").matching("HARD_DEL")
.createQuery();
List results = fullTextEntityManager.createFullTextQuery(luceneQuery, DocVersion.class)
.getResultList();
but instead of results I get:
WARNING: org.hibernate.search.bridge.BridgeException: Exception while calling bridge#objectToString
entity class: com.nws.vedica.model.entity.DocVersion
entity property path: document2.eDocState
field bridge: TwoWayString2FieldBridgeAdaptor [stringBridge=org.hibernate.search.bridge.builtin.EnumBridge@60942b8b]
So what does that mean? Do I need to implement some specific bridge for an Enumeration (how would that look like)?
It's just value enum so I think problem is somewhere else.
Please assist me to get the results.
package I'm using:
hibernate-search-orm: 5.9.3.
java lucene hibernate-search
I am trying to make document index of the Entity that has following associations:
DocVersion:
@Entity
@Indexed
public class DocVersion implements Serializable {
...
@ManyToOne(fetch = FetchType.EAGER, cascade = CascadeType.ALL)
@JoinColumn(name = "doc_uuid")
@IndexedEmbedded
private Document2 document2;
...
}
Document2:
@Entity
@Indexed
public class Document2 implements Serializable {
...
@Column(name = "entityState")
@Enumerated(EnumType.STRING)
@Field(bridge=@FieldBridge(impl=EnumBridge.class), index=Index.YES)
private EDocState eDocState;
...
}
this is how I query the index (just for testing purposes):
FullTextEntityManager fullTextEntityManager = Search.getFullTextEntityManager(entityManager);
try {
fullTextEntityManager.createIndexer().startAndWait();
} catch (InterruptedException e) {
e.printStackTrace();
}
QueryBuilder queryBuilder = fullTextEntityManager.getSearchFactory()
.buildQueryBuilder()
.forEntity(DocVersion.class)
.get();
org.apache.lucene.search.Query luceneQuery = queryBuilder.keyword()
.onField("document2.eDocState").matching("HARD_DEL")
.createQuery();
List results = fullTextEntityManager.createFullTextQuery(luceneQuery, DocVersion.class)
.getResultList();
but instead of results I get:
WARNING: org.hibernate.search.bridge.BridgeException: Exception while calling bridge#objectToString
entity class: com.nws.vedica.model.entity.DocVersion
entity property path: document2.eDocState
field bridge: TwoWayString2FieldBridgeAdaptor [stringBridge=org.hibernate.search.bridge.builtin.EnumBridge@60942b8b]
So what does that mean? Do I need to implement some specific bridge for an Enumeration (how would that look like)?
It's just value enum so I think problem is somewhere else.
Please assist me to get the results.
package I'm using:
hibernate-search-orm: 5.9.3.
java lucene hibernate-search
java lucene hibernate-search
asked Nov 21 '18 at 23:06
greengoldgreengold
4212922
4212922
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
You don't need to implement a specific bridge, actually it's quite the opposite: a bridge is already there, so Hibernate Search expects you to pass enum values to the query, and you're passing String values instead.
Try replacing .matching("HARD_DEL")
with .matching(EDocState.HARD_DEL)
.
Note: I suspect the rest of the stack trace would tell you something about a class cast exception, which could have tipped you off. For your own sake, you should probably not hide stack traces like that, stack traces may contain valuable information.
yeah, that's right. don't know why I didn't try it all day long... maybe I need to tune my logback a little more. thanks.
– greengold
Nov 22 '18 at 10:27
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53421689%2fquery-results-with-hibernate-search-with-associated-enumeration-field%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You don't need to implement a specific bridge, actually it's quite the opposite: a bridge is already there, so Hibernate Search expects you to pass enum values to the query, and you're passing String values instead.
Try replacing .matching("HARD_DEL")
with .matching(EDocState.HARD_DEL)
.
Note: I suspect the rest of the stack trace would tell you something about a class cast exception, which could have tipped you off. For your own sake, you should probably not hide stack traces like that, stack traces may contain valuable information.
yeah, that's right. don't know why I didn't try it all day long... maybe I need to tune my logback a little more. thanks.
– greengold
Nov 22 '18 at 10:27
add a comment |
You don't need to implement a specific bridge, actually it's quite the opposite: a bridge is already there, so Hibernate Search expects you to pass enum values to the query, and you're passing String values instead.
Try replacing .matching("HARD_DEL")
with .matching(EDocState.HARD_DEL)
.
Note: I suspect the rest of the stack trace would tell you something about a class cast exception, which could have tipped you off. For your own sake, you should probably not hide stack traces like that, stack traces may contain valuable information.
yeah, that's right. don't know why I didn't try it all day long... maybe I need to tune my logback a little more. thanks.
– greengold
Nov 22 '18 at 10:27
add a comment |
You don't need to implement a specific bridge, actually it's quite the opposite: a bridge is already there, so Hibernate Search expects you to pass enum values to the query, and you're passing String values instead.
Try replacing .matching("HARD_DEL")
with .matching(EDocState.HARD_DEL)
.
Note: I suspect the rest of the stack trace would tell you something about a class cast exception, which could have tipped you off. For your own sake, you should probably not hide stack traces like that, stack traces may contain valuable information.
You don't need to implement a specific bridge, actually it's quite the opposite: a bridge is already there, so Hibernate Search expects you to pass enum values to the query, and you're passing String values instead.
Try replacing .matching("HARD_DEL")
with .matching(EDocState.HARD_DEL)
.
Note: I suspect the rest of the stack trace would tell you something about a class cast exception, which could have tipped you off. For your own sake, you should probably not hide stack traces like that, stack traces may contain valuable information.
answered Nov 22 '18 at 7:26
yrodiereyrodiere
2,5911315
2,5911315
yeah, that's right. don't know why I didn't try it all day long... maybe I need to tune my logback a little more. thanks.
– greengold
Nov 22 '18 at 10:27
add a comment |
yeah, that's right. don't know why I didn't try it all day long... maybe I need to tune my logback a little more. thanks.
– greengold
Nov 22 '18 at 10:27
yeah, that's right. don't know why I didn't try it all day long... maybe I need to tune my logback a little more. thanks.
– greengold
Nov 22 '18 at 10:27
yeah, that's right. don't know why I didn't try it all day long... maybe I need to tune my logback a little more. thanks.
– greengold
Nov 22 '18 at 10:27
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53421689%2fquery-results-with-hibernate-search-with-associated-enumeration-field%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown