How to interpret a theorem stating that orbits are “uniform on average”












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I am reading through these notes: http://wwwf.imperial.ac.uk/~dcheragh/Teaching/2015-F-DS-MPE.pdf



There is a theorem (Theorem 1 under the section Distribution of Orbits) saying the following: enter image description here



Here $R_{alpha}^k (x)$ is the $k_{th}$ iteration of the rotation by $alpha$ map: $R_alpha(x) = x+alpha (text{mod} 1)$



Question:



There is a comment just above this theorem saying




The distribution of
the orbit is “uniform” on average.




Does this mean that the distributions of orbits on subsets of the circle are also uniform i.e. that if we fix some set $E$ on the circle and wait for the orbit to enter $E$, it has equal probability of landing anywhere in $E$?










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    0












    $begingroup$


    I am reading through these notes: http://wwwf.imperial.ac.uk/~dcheragh/Teaching/2015-F-DS-MPE.pdf



    There is a theorem (Theorem 1 under the section Distribution of Orbits) saying the following: enter image description here



    Here $R_{alpha}^k (x)$ is the $k_{th}$ iteration of the rotation by $alpha$ map: $R_alpha(x) = x+alpha (text{mod} 1)$



    Question:



    There is a comment just above this theorem saying




    The distribution of
    the orbit is “uniform” on average.




    Does this mean that the distributions of orbits on subsets of the circle are also uniform i.e. that if we fix some set $E$ on the circle and wait for the orbit to enter $E$, it has equal probability of landing anywhere in $E$?










    share|cite|improve this question









    $endgroup$















      0












      0








      0





      $begingroup$


      I am reading through these notes: http://wwwf.imperial.ac.uk/~dcheragh/Teaching/2015-F-DS-MPE.pdf



      There is a theorem (Theorem 1 under the section Distribution of Orbits) saying the following: enter image description here



      Here $R_{alpha}^k (x)$ is the $k_{th}$ iteration of the rotation by $alpha$ map: $R_alpha(x) = x+alpha (text{mod} 1)$



      Question:



      There is a comment just above this theorem saying




      The distribution of
      the orbit is “uniform” on average.




      Does this mean that the distributions of orbits on subsets of the circle are also uniform i.e. that if we fix some set $E$ on the circle and wait for the orbit to enter $E$, it has equal probability of landing anywhere in $E$?










      share|cite|improve this question









      $endgroup$




      I am reading through these notes: http://wwwf.imperial.ac.uk/~dcheragh/Teaching/2015-F-DS-MPE.pdf



      There is a theorem (Theorem 1 under the section Distribution of Orbits) saying the following: enter image description here



      Here $R_{alpha}^k (x)$ is the $k_{th}$ iteration of the rotation by $alpha$ map: $R_alpha(x) = x+alpha (text{mod} 1)$



      Question:



      There is a comment just above this theorem saying




      The distribution of
      the orbit is “uniform” on average.




      Does this mean that the distributions of orbits on subsets of the circle are also uniform i.e. that if we fix some set $E$ on the circle and wait for the orbit to enter $E$, it has equal probability of landing anywhere in $E$?







      probability ergodic-theory






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      asked Dec 5 '18 at 21:23









      foshofosho

      4,7771031




      4,7771031






















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          If the set $E$ has positive measure, yes.






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            $begingroup$

            If the set $E$ has positive measure, yes.






            share|cite|improve this answer









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              $begingroup$

              If the set $E$ has positive measure, yes.






              share|cite|improve this answer









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                $begingroup$

                If the set $E$ has positive measure, yes.






                share|cite|improve this answer









                $endgroup$



                If the set $E$ has positive measure, yes.







                share|cite|improve this answer












                share|cite|improve this answer



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                answered Dec 5 '18 at 21:47









                kodlukodlu

                3,390716




                3,390716






























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