How to store (and load) a zsh String array to a file?
I want to store an array of some quotes (so basically real-world strings with new lines) in a file. How can I achieve it? I thought of setting the IFS to something like “xxxxxxxxx74765xxx” (which will never occur in my strings), but of course, IFS only works for single chars.
I can think of some ugly hacks to do it (e.g., store that nonsense string as a line between elements, read the file line by line and check each line against it, and rebuild the array thus.), but I will appreciate some more experienced opinions.
zsh array
edited Dec 9 '18 at 14:27
Jeff Schaller
39.3k1054125
asked Dec 5 '18 at 20:11
HappyFaceHappyFace
31811
add a comment |
I want to store an array of some quotes (so basically real-world strings with new lines) in a file. How can I achieve it? I thought of setting the IFS to something like “xxxxxxxxx74765xxx” (which will never occur in my strings), but of course, IFS only works for single chars.
I can think of some ugly hacks to do it (e.g., store that nonsense string as a line between elements, read the file line by line and check each line against it, and rebuild the array thus.), but I will appreciate some more experienced opinions.
zsh array
edited Dec 9 '18 at 14:27
Jeff Schaller
39.3k1054125
asked Dec 5 '18 at 20:11
HappyFaceHappyFace
31811
add a comment |
I want to store an array of some quotes (so basically real-world strings with new lines) in a file. How can I achieve it? I thought of setting the IFS to something like “xxxxxxxxx74765xxx” (which will never occur in my strings), but of course, IFS only works for single chars.
I can think of some ugly hacks to do it (e.g., store that nonsense string as a line between elements, read the file line by line and check each line against it, and rebuild the array thus.), but I will appreciate some more experienced opinions.
zsh array
edited Dec 9 '18 at 14:27
Jeff Schaller
39.3k1054125
asked Dec 5 '18 at 20:11
HappyFaceHappyFace
31811
I want to store an array of some quotes (so basically real-world strings with new lines) in a file. How can I achieve it? I thought of setting the IFS to something like “xxxxxxxxx74765xxx” (which will never occur in my strings), but of course, IFS only works for single chars.
I can think of some ugly hacks to do it (e.g., store that nonsense string as a line between elements, read the file line by line and check each line against it, and rebuild the array thus.), but I will appreciate some more experienced opinions.
zsh array
zsh array
edited Dec 9 '18 at 14:27
Jeff Schaller
39.3k1054125
asked Dec 5 '18 at 20:11
HappyFaceHappyFace
31811
edited Dec 9 '18 at 14:27
Jeff Schaller
39.3k1054125
asked Dec 5 '18 at 20:11
HappyFaceHappyFace
31811
edited Dec 9 '18 at 14:27
Jeff Schaller
39.3k1054125
edited Dec 9 '18 at 14:27
Jeff Schaller
39.3k1054125
edited Dec 9 '18 at 14:27
Jeff Schaller
39.3k1054125
39.3k1054125
asked Dec 5 '18 at 20:11
HappyFaceHappyFace
31811
asked Dec 5 '18 at 20:11
HappyFaceHappyFace
31811
asked Dec 5 '18 at 20:11
HappyFaceHappyFace
31811
31811
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
Just do:
typeset array > file
To load:
source file
(you can also use typeset -p array to also save the attributes of the array variable (exported, unique...)).
Alternatively:
print -rl -- ${(qq)array} > file
To load:
eval "array=($(<file))"
For your separator idea:
print -r -- ${(j:separator:)array} > file
To load:
array=("${(@s:separator:)"$(<file)")
(though beware it removes all trailing newline characters from the last element of the array and it doesn't work for an empty array).
answered Dec 5 '18 at 20:32
Stéphane ChazelasStéphane Chazelas
301k55564916
add a comment |
The two portable (ksh, zsh, bash) solutions AFAICT are:
typeset -p arr >./file # save array
. ./file # read array
And
printf '%qn' "${arr[@]}" >./file # save array
eval "arr=( $(< ./file) )" # read array
Note that the first solution will create a local variable if used inside a function in bash.
answered Dec 6 '18 at 9:17
IsaacIsaac
11.4k11652
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Just do:
typeset array > file
To load:
source file
(you can also use typeset -p array to also save the attributes of the array variable (exported, unique...)).
Alternatively:
print -rl -- ${(qq)array} > file
To load:
eval "array=($(<file))"
For your separator idea:
print -r -- ${(j:separator:)array} > file
To load:
array=("${(@s:separator:)"$(<file)")
(though beware it removes all trailing newline characters from the last element of the array and it doesn't work for an empty array).
answered Dec 5 '18 at 20:32
Stéphane ChazelasStéphane Chazelas
301k55564916
add a comment |
Just do:
typeset array > file
To load:
source file
(you can also use typeset -p array to also save the attributes of the array variable (exported, unique...)).
Alternatively:
print -rl -- ${(qq)array} > file
To load:
eval "array=($(<file))"
For your separator idea:
print -r -- ${(j:separator:)array} > file
To load:
array=("${(@s:separator:)"$(<file)")
(though beware it removes all trailing newline characters from the last element of the array and it doesn't work for an empty array).
answered Dec 5 '18 at 20:32
Stéphane ChazelasStéphane Chazelas
301k55564916
add a comment |
Just do:
typeset array > file
To load:
source file
(you can also use typeset -p array to also save the attributes of the array variable (exported, unique...)).
Alternatively:
print -rl -- ${(qq)array} > file
To load:
eval "array=($(<file))"
For your separator idea:
print -r -- ${(j:separator:)array} > file
To load:
array=("${(@s:separator:)"$(<file)")
(though beware it removes all trailing newline characters from the last element of the array and it doesn't work for an empty array).
answered Dec 5 '18 at 20:32
Stéphane ChazelasStéphane Chazelas
301k55564916
Just do:
typeset array > file
To load:
source file
(you can also use typeset -p array to also save the attributes of the array variable (exported, unique...)).
Alternatively:
print -rl -- ${(qq)array} > file
To load:
eval "array=($(<file))"
For your separator idea:
print -r -- ${(j:separator:)array} > file
To load:
array=("${(@s:separator:)"$(<file)")
(though beware it removes all trailing newline characters from the last element of the array and it doesn't work for an empty array).
answered Dec 5 '18 at 20:32
Stéphane ChazelasStéphane Chazelas
301k55564916
edited Dec 5 '18 at 20:49
answered Dec 5 '18 at 20:32
Stéphane ChazelasStéphane Chazelas
301k55564916
answered Dec 5 '18 at 20:32
Stéphane ChazelasStéphane Chazelas
301k55564916
answered Dec 5 '18 at 20:32
Stéphane ChazelasStéphane Chazelas
301k55564916
301k55564916
add a comment |
add a comment |
The two portable (ksh, zsh, bash) solutions AFAICT are:
typeset -p arr >./file # save array
. ./file # read array
And
printf '%qn' "${arr[@]}" >./file # save array
eval "arr=( $(< ./file) )" # read array
Note that the first solution will create a local variable if used inside a function in bash.
answered Dec 6 '18 at 9:17
IsaacIsaac
11.4k11652
add a comment |
The two portable (ksh, zsh, bash) solutions AFAICT are:
typeset -p arr >./file # save array
. ./file # read array
And
printf '%qn' "${arr[@]}" >./file # save array
eval "arr=( $(< ./file) )" # read array
Note that the first solution will create a local variable if used inside a function in bash.
answered Dec 6 '18 at 9:17
IsaacIsaac
11.4k11652
add a comment |
The two portable (ksh, zsh, bash) solutions AFAICT are:
typeset -p arr >./file # save array
. ./file # read array
And
printf '%qn' "${arr[@]}" >./file # save array
eval "arr=( $(< ./file) )" # read array
Note that the first solution will create a local variable if used inside a function in bash.
answered Dec 6 '18 at 9:17
IsaacIsaac
11.4k11652
The two portable (ksh, zsh, bash) solutions AFAICT are:
typeset -p arr >./file # save array
. ./file # read array
And
printf '%qn' "${arr[@]}" >./file # save array
eval "arr=( $(< ./file) )" # read array
Note that the first solution will create a local variable if used inside a function in bash.
answered Dec 6 '18 at 9:17
IsaacIsaac
11.4k11652
answered Dec 6 '18 at 9:17
IsaacIsaac
11.4k11652
answered Dec 6 '18 at 9:17
IsaacIsaac
11.4k11652
answered Dec 6 '18 at 9:17
IsaacIsaac
11.4k11652
11.4k11652
add a comment |
add a comment |
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