plotting error_only size-1 arrays can be converted to Python scalars
I want to plot a function and each time I got this error: only size-1 arrays can be converted to Python scalars.
I want to plot my function over the w.
The code is :
import matplotlib.pyplot as plt
import numpy as np
import math
a = 10;
w = np.arange (0.001,10, 0.1)
function = (1/(np.pi*(w**2))+ np.pi)*abs(((-2*math.atan(a))*w)-(2*math.atanh(((w**2) + 1)/(-1*(w**2) + 2*(a**2) +1))*w)+ (np.pi*w) -(2*math.atanh(w/(a))))
plt.plot(w, function)
plt.show()
Thanks for your time.
python plot
asked Nov 21 '18 at 23:02
Amir Reza JalaliAmir Reza Jalali
156
add a comment |
I want to plot a function and each time I got this error: only size-1 arrays can be converted to Python scalars.
I want to plot my function over the w.
The code is :
import matplotlib.pyplot as plt
import numpy as np
import math
a = 10;
w = np.arange (0.001,10, 0.1)
function = (1/(np.pi*(w**2))+ np.pi)*abs(((-2*math.atan(a))*w)-(2*math.atanh(((w**2) + 1)/(-1*(w**2) + 2*(a**2) +1))*w)+ (np.pi*w) -(2*math.atanh(w/(a))))
plt.plot(w, function)
plt.show()
Thanks for your time.
python plot
asked Nov 21 '18 at 23:02
Amir Reza JalaliAmir Reza Jalali
156
add a comment |
I want to plot a function and each time I got this error: only size-1 arrays can be converted to Python scalars.
I want to plot my function over the w.
The code is :
import matplotlib.pyplot as plt
import numpy as np
import math
a = 10;
w = np.arange (0.001,10, 0.1)
function = (1/(np.pi*(w**2))+ np.pi)*abs(((-2*math.atan(a))*w)-(2*math.atanh(((w**2) + 1)/(-1*(w**2) + 2*(a**2) +1))*w)+ (np.pi*w) -(2*math.atanh(w/(a))))
plt.plot(w, function)
plt.show()
Thanks for your time.
python plot
asked Nov 21 '18 at 23:02
Amir Reza JalaliAmir Reza Jalali
156
I want to plot a function and each time I got this error: only size-1 arrays can be converted to Python scalars.
I want to plot my function over the w.
The code is :
import matplotlib.pyplot as plt
import numpy as np
import math
a = 10;
w = np.arange (0.001,10, 0.1)
function = (1/(np.pi*(w**2))+ np.pi)*abs(((-2*math.atan(a))*w)-(2*math.atanh(((w**2) + 1)/(-1*(w**2) + 2*(a**2) +1))*w)+ (np.pi*w) -(2*math.atanh(w/(a))))
plt.plot(w, function)
plt.show()
Thanks for your time.
python plot
python plot
asked Nov 21 '18 at 23:02
Amir Reza JalaliAmir Reza Jalali
156
asked Nov 21 '18 at 23:02
Amir Reza JalaliAmir Reza Jalali
156
asked Nov 21 '18 at 23:02
Amir Reza JalaliAmir Reza Jalali
156
asked Nov 21 '18 at 23:02
Amir Reza JalaliAmir Reza Jalali
156
asked Nov 21 '18 at 23:02
Amir Reza JalaliAmir Reza Jalali
156
156
add a comment |
add a comment |
1 Answer
1
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oldest
votes
You'll be better off using numpy.arctan and numpy.arctanh instead of the math equivalents, as they can work with arrays:
a = 10;
w = np.arange (0.001,10, 0.1)
function = (1/(np.pi*(w**2))+ np.pi)*abs(((-2*np.arctan(a))*w)-(2*np.arctanh(((w**2) + 1)/(-1*(w**2) + 2*(a**2) +1))*w)+ (np.pi*w) -(2*np.arctanh(w/(a))))
plt.plot(w, function)
plt.show()
answered Nov 21 '18 at 23:06
saculsacul
30k41740
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You'll be better off using numpy.arctan and numpy.arctanh instead of the math equivalents, as they can work with arrays:
a = 10;
w = np.arange (0.001,10, 0.1)
function = (1/(np.pi*(w**2))+ np.pi)*abs(((-2*np.arctan(a))*w)-(2*np.arctanh(((w**2) + 1)/(-1*(w**2) + 2*(a**2) +1))*w)+ (np.pi*w) -(2*np.arctanh(w/(a))))
plt.plot(w, function)
plt.show()
answered Nov 21 '18 at 23:06
saculsacul
30k41740
add a comment |
You'll be better off using numpy.arctan and numpy.arctanh instead of the math equivalents, as they can work with arrays:
a = 10;
w = np.arange (0.001,10, 0.1)
function = (1/(np.pi*(w**2))+ np.pi)*abs(((-2*np.arctan(a))*w)-(2*np.arctanh(((w**2) + 1)/(-1*(w**2) + 2*(a**2) +1))*w)+ (np.pi*w) -(2*np.arctanh(w/(a))))
plt.plot(w, function)
plt.show()
answered Nov 21 '18 at 23:06
saculsacul
30k41740
add a comment |
You'll be better off using numpy.arctan and numpy.arctanh instead of the math equivalents, as they can work with arrays:
a = 10;
w = np.arange (0.001,10, 0.1)
function = (1/(np.pi*(w**2))+ np.pi)*abs(((-2*np.arctan(a))*w)-(2*np.arctanh(((w**2) + 1)/(-1*(w**2) + 2*(a**2) +1))*w)+ (np.pi*w) -(2*np.arctanh(w/(a))))
plt.plot(w, function)
plt.show()
answered Nov 21 '18 at 23:06
saculsacul
30k41740
You'll be better off using numpy.arctan and numpy.arctanh instead of the math equivalents, as they can work with arrays:
a = 10;
w = np.arange (0.001,10, 0.1)
function = (1/(np.pi*(w**2))+ np.pi)*abs(((-2*np.arctan(a))*w)-(2*np.arctanh(((w**2) + 1)/(-1*(w**2) + 2*(a**2) +1))*w)+ (np.pi*w) -(2*np.arctanh(w/(a))))
plt.plot(w, function)
plt.show()
answered Nov 21 '18 at 23:06
saculsacul
30k41740
answered Nov 21 '18 at 23:06
saculsacul
30k41740
answered Nov 21 '18 at 23:06
saculsacul
30k41740
answered Nov 21 '18 at 23:06
saculsacul
30k41740
30k41740
add a comment |
add a comment |
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